find the area of the circle, the subtract the area of the rectangle
you know that the diameter of the circle is 9 so that should help you get the area of the circle
then use phythagorean thereom to get the area of one triangle and multiply it times 2 to get the area of both triangles
the subtract the area if the circle and the area of the rectangle
51 Is 3% Of 1,700. I Would Expect This Number To Be A Lot Greater Than 51 Because Its Only A Smaller Percent Of The Larger Number.
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Okay, you will need to use the law of cosines for this problem.
The Law of Cosines states (in this case): a^2 = b^2 + c^2 - 2 * b * c * cos A, where "a" is the side opposite angle A (7 inches), and b and c are the other two sides.
Plug the numbers in and you get: 7^2 = 5^2 + 9^2 - 2 * 5 * 9 * cos A, or:
49 = 25 + 81 - 90 * cos A.
Subtract (25 + 81) from both sides to get:
-57 = -90 * cos A.
Divide by -90 on both sides:
cos A = 19/30
To find A, you do the inverse trigonometric function to get:
cos^-1 of (19/30) = A.
I don't have a calculator that can do this right now, but if you plug the left side of the above equation into it (make sure it is in degrees, not radians), you should get A.
5(10) - 2(3) , 50 - 6 , 44
