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atroni [7]
2 years ago
10

In the equation 3x+4=13, the 4 and 13 are called what?

Mathematics
2 answers:
alex41 [277]2 years ago
6 0
Constant is the answer
Yakvenalex [24]2 years ago
6 0

In the given equation :

  • 3x + 4 = 13

4 and 13 are Constants

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Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

8 0
2 years ago
Kevin traveled at a constant speed on the highway from Hickory Hills to Chicago in 20 minutes. The distance from Hickory Hills t
beks73 [17]

Answer: V=51\ \frac{mi}{h}

Step-by-step explanation:

You need to used the following formula:

V=\frac{d}{t}

Where "V" is the speed, "d" is the distance and "t" is the time.

In this case you know that Kevin traveled at a constant speed on the highway from Hickory Hills to Chicago in 20 minutes (which is \frac{1}{3}\ h) and the distance is 17 miles. Then, you can identify that:

t=\frac{1}{3}\ h\\\\d=17\ mi

Therefore, knowing these values, you can substitute them into the formula. Then, you get:

V=\frac{17\ mi}{\frac{1}{3}\ h}\\\\V=51\ \frac{mi}{h}

8 0
3 years ago
Trigonometric identities: Performance task
MakcuM [25]

#1

\\ \sf\longmapsto (1+cosx)(1-cosx)

\\ \sf\longmapsto 1-cos^2x

\\ \sf\longmapsto sin^2x

#2

\\ \sf\longmapsto \dfrac{1}{cot^2x}-\dfrac{1}{cos^2x}

\\ \sf\longmapsto tan^2x-sec^2x

\\ \sf\longmapsto 1

3 0
3 years ago
Read 2 more answers
What is the length of AC?
sashaice [31]

A is at -8 and C i5 at 5

-8 to 0 is 8 units and 0 to 5 is 5 units.

8 +5 = 13

AC is 13 units long.

3 0
3 years ago
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Find m <br> Help, I really don't understand this
Irina18 [472]
m\angle B=m\angle C\\&#10;m\angle C=180-100=80 \Rightarrow m\angle B=80
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3 years ago
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