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tia_tia [17]
2 years ago
13

Sandesh bought two books for Rs 480.He sold them to attain 19% profit on one and 15% loss on the other. Calculate his final gain

or loss percent if the selling price of both watches is the same.
Mathematics
1 answer:
slamgirl [31]2 years ago
7 0

Answer:

answer = profit 14.166%

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A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da
allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation S'(t)= -30t^{2} + 420t. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\  S(t)= -10t^{3} +210t^{2} \\

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

Given\ S(t) = -10t^{3} + 210t^{2}

S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

8 0
3 years ago
An inequality is shown below.
Stells [14]
B.
You are looking for something that does not let 25x go over 80.
8 0
3 years ago
Can someone help me out????
Marta_Voda [28]

Answer:

NO

Step-by-step explanation:

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u

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aut

tis

umm

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special

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home

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6 0
3 years ago
Please help me. I need help
koban [17]
I am pretty sure the answer would be -.02
Bc you would do 2-3.6/5- -3
3 0
3 years ago
Help Please :D!!!!!! v
Amiraneli [1.4K]

Answer:

A they are just reflected over the y axis

Step-by-step explanation:

5 0
3 years ago
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