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Irina18 [472]
2 years ago
8

Help!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Zolol [24]2 years ago
6 0

I hope it will help you .

Thank you.

<em><u>Tedy</u></em><em><u>bear</u></em><em><u>l</u></em><em><u>over</u></em><em><u> </u></em>

^ - ^

MariettaO [177]2 years ago
4 0

Step-by-step explanation:

5 \: mile =  > 8km \\ 60 \: mile =  > x \\ 5x = 60 \times 8 \\ 5x = 480 \\ x =  \frac{480}{5}  \\ x = 96  \\ thank \: you

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Sketch and label two different kites each with area 1092 cm2
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Answer:

Step-by-step explanation:

one could be a square with side length of SQRT(1092)

The other could be a rectangle or a circle or an ellispe

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2 years ago
Evaluate the expression when r = 8.2 and s = –3.7.
kiruha [24]
When you plug in the numbers for the integers, you get
8.2-2(-3.7)
If you multiply -2 and -3.7, you get 7.4 because the negatives cancel each other out.
If you then add 8.2, you get 15.6. So the answer is D.
Hope it Helps!  :)
8 0
3 years ago
Find the 50th term of 15, 9, 3, -3,...
MA_775_DIABLO [31]

Answer:-32 I THINK IM NOT 100 PERCENT POSITIVE

Step-by-step explanation:

8 0
3 years ago
Help please i want help please
Rasek [7]
Don't listen but i'm gonna go with the third one
3 0
3 years ago
Suppose that many large samples are taken from a population and that the
rewona [7]

Answer:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

\bar X = 0.22

And the standard error is given by:

SE = 0.029

We want to construct a 68% confidence interval so then the significance level would be :

\alpha=1-0.68 = 0.32 and \alpha/2 =0.16. The confidence interval is given by:

\bar X \pm z_{\alpha/2} SE

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

z_{\alpha/2}= 1

And replacing we got:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

5 0
2 years ago
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