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Mrrafil [7]
2 years ago
14

Https://forms.gle/eP8F5eKC2AUaCsB67

Computers and Technology
1 answer:
Deffense [45]2 years ago
3 0

Answer:

NO .THATS NOT A GOOD QUESTIONS.

Explanation:THOSE R PERSONAL

You might be interested in
first 2 questions are true or false the last question is multiple choice. 7th grade work. plz only answer if u know.
pshichka [43]

#4 is true

We use pseudocode to help us understand code.

#5 is false

Strings are surrounded by quotes, integers are not.

#6 is 100.

Integers are numbers with no decimal places.

3 0
3 years ago
Define a class called TreeNode containing three data fields: element, left and right. The element is a generic type. Create cons
m_a_m_a [10]

Answer:

See explaination

Explanation:

// Class for BinarySearchTreeNode

class TreeNode

{

// To store key value

public int key;

// To point to left child

public TreeNode left;

// To point to right child

public TreeNode right;

// Default constructor to initialize instance variables

public TreeNode(int key)

{

this.key = key;

left = null;

right = null;

key = 0;

}// End of default constructor

}// End of class

// Defines a class to crate binary tree

class BinaryTree

{

// Creates root node

TreeNode root;

int numberElement;

// Default constructor to initialize root

public BinaryTree()

{

this.root = null;

numberElement = 0;

}// End of default constructor

// Method to insert key

public void insert(int key)

{

// Creates a node using parameterized constructor

TreeNode newNode = new TreeNode(key);

numberElement++;

// Checks if root is null then this node is the first node

if(root == null)

{

// root is pointing to new node

root = newNode;

return;

}// End of if condition

// Otherwise at least one node available

// Declares current node points to root

TreeNode currentNode = root;

// Declares parent node assigns null

TreeNode parentNode = null;

// Loops till node inserted

while(true)

{

// Parent node points to current node

parentNode = currentNode;

// Checks if parameter key is less than the current node key

if(key < currentNode.key)

{

// Current node points to current node left

currentNode = currentNode.left;

// Checks if current node is null

if(currentNode == null)

{

// Parent node left points to new node

parentNode.left = newNode;

return;

}// End of inner if condition

}// End of outer if condition

// Otherwise parameter key is greater than the current node key

else

{

// Current node points to current node right

currentNode = currentNode.right;

// Checks if current node is null

if(currentNode == null)

{

// Parent node right points to new node

parentNode.right = newNode;

return;

}// End of inner if condition

}// End of outer if condition

}// End of while

}// End of method

// Method to check tree is balanced or not

private int checkBalance(TreeNode currentNode)

{

// Checks if current node is null then return 0 for balanced

if (currentNode == null)

return 0;

// Recursively calls the method with left child and

// stores the return value as height of left sub tree

int leftSubtreeHeight = checkBalance(currentNode.left);

// Checks if left sub tree height is -1 then return -1

// for not balanced

if (leftSubtreeHeight == -1)

return -1;

// Recursively calls the method with right child and

// stores the return value as height of right sub tree

int rightSubtreeHeight = checkBalance(currentNode.right);

// Checks if right sub tree height is -1 then return -1

// for not balanced

if (rightSubtreeHeight == -1) return -1;

// Checks if left and right sub tree difference is greater than 1

// then return -1 for not balanced

if (Math.abs(leftSubtreeHeight - rightSubtreeHeight) > 1)

return -1;

// Returns the maximum value of left and right subtree plus one

return (Math.max(leftSubtreeHeight, rightSubtreeHeight) + 1);

}// End of method

// Method to calls the check balance method

// returns false for not balanced if check balance method returns -1

// otherwise return true for balanced

public boolean balanceCheck()

{

// Calls the method to check balance

// Returns false for not balanced if method returns -1

if (checkBalance(root) == -1)

return false;

// Otherwise returns true

return true;

}//End of method

// Method for In Order traversal

public void inorder()

{

inorder(root);

}//End of method

// Method for In Order traversal recursively

private void inorder(TreeNode root)

{

// Checks if root is not null

if (root != null)

{

// Recursively calls the method with left child

inorder(root.left);

// Displays current node value

System.out.print(root.key + " ");

// Recursively calls the method with right child

inorder(root.right);

}// End of if condition

}// End of method

}// End of class BinaryTree

// Driver class definition

class BalancedBinaryTreeCheck

{

// main method definition

public static void main(String args[])

{

// Creates an object of class BinaryTree

BinaryTree treeOne = new BinaryTree();

// Calls the method to insert node

treeOne.insert(1);

treeOne.insert(2);

treeOne.insert(3);

treeOne.insert(4);

treeOne.insert(5);

treeOne.insert(8);

// Calls the method to display in order traversal

System.out.print("\n In order traversal of Tree One: ");

treeOne.inorder();

if (treeOne.balanceCheck())

System.out.println("\n Tree One is balanced");

else

System.out.println("\n Tree One is not balanced");

BinaryTree

BinaryTree treeTwo = new BinaryTree();

treeTwo.insert(10);

treeTwo.insert(18);

treeTwo.insert(8);

treeTwo.insert(14);

treeTwo.insert(25);

treeTwo.insert(9);

treeTwo.insert(5);

System.out.print("\n\n In order traversal of Tree Two: ");

treeTwo.inorder();

if (treeTwo.balanceCheck())

System.out.println("\n Tree Two is balanced");

else

System.out.println("\n Tree Two is not balanced");

}// End of main method

}// End of driver class

5 0
3 years ago
Output values below an amount Write a program that first gets a list of integers from input. The input begins with an integer in
Katarina [22]

The program that first gets a list of integers from input, gets the last value from the input, which indicates a threshold, and outputs all integers less than or equal to that last threshold value is:

import java.util.Scanner;

public class LabProgram {

 /* Define your methods here */

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int[] userValues = new int[20];

int upperThreshold;

int numVals;

numVals = scnr.nextInt();

GetUserValues(userValues, numVals, scnr);

upperThreshold = scnr.nextInt();

OutputIntsLessThanOrEqualToThreshold(userValues, numVals, upperThreshold);

}

}

Read more about java programming here:

brainly.com/question/26952414

#SPJ1

6 0
2 years ago
What are creative commons?
Olenka [21]

Answer:

c

Explanation:

4 0
3 years ago
Read 2 more answers
It is a well-researched fact that men in a restroom generally prefer to maximizetheir distance from already occupied stalls, by
Artyom0805 [142]

Answer:

The code below addresses the problem statement with appropriate comments for explanation.

Explanation:

public class Stall

{

public static void main(String[] args)

{

boolean[] arr = new boolean[10];

while(hasFreeSpots(arr))   // as long as there is a free slot

{

arr[position(arr)] = true;  

// position(arr) gets the position of slot a person would most likely enter at(view problem statement)

// setting that position true(position occupied) by arr[position(arr)]

System.out.println(stallView(arr));   // printing current state of the stall using 'X' and '_'

}

}

/**

* Find the empty position that is in the middle of the sub-array of largest group of empty spots

* @param arr an array of boolean values

* @return returns an an integer value. Optimal position to be occupied.

*/

public static int position(boolean[] arr)

{

int first = 0;   // first stores the starting position of "longest sequence of unoccupied places"

int last = 0;   // last stores the ending position of "longest sequence of unoccupied places"

int temp1 = 0;   // temp1 stores the starting position of "current sequence of unoccupied places"

int temp2 = 0; // temp2 stores the ending position of "current sequence of unoccupied places"

 

for(int i = 0; i < arr.length; i++)   // for each slot in the Stall

{    

if(!arr[i]) // if slot i is not occupied

{    

temp1 = i;   // store starting position of "current sequence of unoccupied places" in temp1

while(i < arr.length && !arr[i] )   // if i is a valid index and as long as this slot is not occupied increment i

{

i++;

}

// we break out of the loop either if i is invalid index(reached end of the array)

// or if the slot is occupied by a person already

temp2 = i;   // store ending position of "current sequence of unoccupied places" in temp2

if(Math.abs(first - last) < Math.abs(temp1 - temp2))

  // if current sequence is longer than longest sequence, update it

{

first = temp1;

last = temp2;    

}

}

}

return (first + last) / 2;   // return middle index of first and last

}

/**

* Checks if there are empty spots in an array, basically checks if there is a false boolean value

* thats representing an empty spot in an array

* @param arr the input array, of boolean values

* @return returns a boolean value, true if there are false elements inside the array

*/

public static boolean hasFreeSpots(boolean[] arr)

{

boolean rtn = true;   // initializing rtn to 'true'

for(int i = 0; i < arr.length; i++)   // for every slot in the Stall

{

if(!arr[i]){rtn = false;}   // sets rtn to false if a free spot found

}

return !rtn;   // returns true if a free spot found and returns false if no free spot found

}

/**

* X for true, _ for false. Representing occupied(X) and free stalls(_)

* @param arr a boolean array

* @return returns a string representation if the input

*/

public static String stallView(boolean[] arr)

{

String str = "";       // initializing str to be an empty String

for(int i = 0; i < arr.length; i++)   // for every slot in Stall

{

if(arr[i]){str += " X";}   // Add X to str if slot is occupied

else {str += " _";}           // prints _ to str if slot not occupied

}

return str;       // return str(pictorial representation of Stall with 'X', '_')

}

}

7 0
3 years ago
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