Answer:
r = 225 Mil/h speed of the airplane in still air
Step-by-step explanation:
Then:
d is traveled distance and r the speed of the airplane in still air
so the first equation is for a 4 hours trip
as d = v*t
d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)
Second equation the trip back in 5 hours
d = 5 * ( r - 25 ) (2)
So we got a system of two equation and two unknown variables d and
r
We solve it by subtitution
from equation (1) d = 4r + 100
plugging in equation 2
4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h
And distance is :
d = 4*r + 100 ⇒ d = 4 * ( 225) + 100
d = 900 + 100
d = 1000 miles
Answer:
2√5
Step-by-step explanation:
d = √(x2 - x1)² + (y2 - y1)²
= √[1 - (-1)]² + [3 - (-1)]
= √(2)² + (4)²
= √(4) + (16)
= √20
= 2√5
5x-10=3x+40
5x=3x+50
2x=50
x=25
5*25=125
125-10=115
angle AEB=115
Hope this helps :)
