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2 years ago

Derivation of trigonometric identities (all 3).

Mathematics

1 answer:

skad [1K]2 years ago

6 0

Answer:

Sine, Cosine and Tangent.

Step-by-step explanation:

These are the 3 basic trigonometric identities.

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I need help plz..... ☺

Kamila [148]

It's 42, here's a quick trick to do this, so we know there's 7 movies, and to find the combination we know we can't choose 2 of the same movie, so to make this part easier , in your head take one movie from the stack out of the stack now there's 6 movies. It's now just the "plug and play" step , (7)*(6)=(42)
I'm sorry If this is to long of an explanation, but I hope that this helps you understand on how to do this problem. Have a nice day :)

4 0

3 years ago

Read 2 more answers

Select the correct answer.

oksano4ka [1.4K]

Answer: $\dfrac{1}{3}$

Step-by-step explanation:

Favorable outcomes (sum is a multiple of 3): (1,2) , (1, 5), (1,8), (2,1) , (2,4), (2,7) , (3, 3), (3, 6), (4, 2), (4, 5) , (4, 8), (5,1), (5, 4), (5, 7), (6,3), (6, 6).

Number of favorable outcomes (sum is a multiple of 3): 16

Total outcomes = Total outcomes of 6-sided die x Total outcomes of 8-sided die=6 × 8 = 48

Then , the probability of getting numbers whose sum is a multiple of 3:

$=\dfrac{\text{favorable outcomes}}{\text{total outcomes}}\\\\=\dfrac{16}{48}=\dfrac{1}{3}$

Hence, the required probability = $\dfrac{1}{3}$

7 0

3 years ago

On a coordinate plane, a line has points (negative 2, negative 4) and (4, 2). Point P is at (0, 4). Which points lie on the line

NikAS [45]

Answer:

the correct options are:

(–1, 3), (–2, 2) and (–5, –1)

Step-by-step explanation:

Given that a line passes through two points

A(-2, -4) and B(4, 2)

Another point P(0, 4)

To find:

Which points lie on the line that passes through P and is parallel to line AB ?

Solution:

First of all, let us the find the equation of the line which is parallel to AB and passes through point P.

Parallel lines have the same slope.

Slope of a line is given as:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{2-(-4)}{4-(-2)} = 1$

Now, using slope intercept form ( $y = mx+c$ ) of a line, we can write the equation of line parallel to AB:

$y =(1)x+c \Rightarrow y = x+c$

Now, putting the point P(0,4) to find c:

$4 = 0 +c \Rightarrow c = 4$

So, the equation is $\bold{y=x+4}$

So, the coordinates given in the options which have value of y coordinate equal to 4 greater than x coordinate will be true.

So, the correct options are:

(–1, 3), (–2, 2) and (–5, –1)

8 0

3 years ago

Read 2 more answers

1 What is the slope of the line through (-9,-6) and (3,-9)?

Setler [38]

Answer:

-2/3

Step-by-step explanation:

So the slope of the line that goes through the points and is m=3/2

Now flip the fraction and change the sign to get the answer -2/3

PLZ MARK AS BRAINLYEST

5 0

3 years ago

Read 2 more answers

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$