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Dmitriy789 [7]
3 years ago
13

When Famke charges her phone, it gains 222 percentage points each minute. When Famke uses her phone, it loses 555 percentage poi

nts each minute. Once, Famke used her phone for some time, and then charged it for twice the amount of time she used it. In the end, her phone lost 101010 percentage points. How long did Famke use her phone and how long did she charge it?
Mathematics
2 answers:
Charra [1.4K]3 years ago
6 0
To answer this you can use a guess and check strategy.

Start with 5 minutes using it (25% lost) and 10 minutes charging (20% gained).

Try 7 minutes using it (35% lost) and 14 minutes charging (28%).

Next, 9 minutes (45%) and 18 minutes(36%).

10 minutes (50%) and 20 minutes (40%). This is the difference.

She used it for 10 minutes and charged it for 20 minutes.
kolbaska11 [484]3 years ago
4 0

Answer:  Famke uses her phone for 10 minutes and she charge it for 20 minutes .

Step-by-step explanation:

Let x be the number of hours Famke charges her phone.

Let y be the number of hours Famke uses her phone.

According to question, he charged it for twice the amount of time she used it.

So, it becomes

x=2y\\\\x-2y=0-----(1)

Number of points he gain while charging her phone = 2%

Number of points he loses while used her phone = 5%

Total points he lost = 10%

So, our equation would be

0.02x-0.05y=-0.10-----(2)

Put the value of x in the eq(2).

0.02\times 2y-0.05y=-0.10\\\\0.04y-0.05y=-0.10\\\\-0.01y=-0.10\\\\y=10

and x=2×10=20 minutes

Hence, Famke uses her phone for 10 minutes and she charge it for 20 minutes.

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