Answer:
(1, 1 )
Step-by-step explanation:
Given the 2 equations
2x + 3y = 5 → (1)
7x - 5y = 2 → (2)
Multiplying (1) by 5 and (2) by 3 and adding will eliminate the y- term
10x + 15y = 25 → (3)
21x - 15y = 6 → (4)
Add (3) and (4) term by term to eliminate y
31x = 31 ( divide both sides by 31 )
x = 1
Substitute x = 1 into either of the 2 equations and evaluate for y
Substituting into (1)
2(1) + 3y = 5
2 + 3y = 5 ( subtract 2 from both sides )
3y = 3 ( divide both sides by 3 )
y = 1
Solution is (1, 1 )
6 ft 3 inches
1 inch = 0.0833 ft.
1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula
to find the distance from point
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer:
.
Answer:
132−15+12
Step-by-step explanation: