Answer:
![\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D%5Ccdot%5Csqrt%5B3%5D%7B5%7D%20%3D%5Csqrt%5B6%5D%7B5%5E3%7D%20%5Ccdot%5Csqrt%5B6%5D%7B5%5E2%7D%20%3D%5Csqrt%5B6%5D%7B5%5E5%7D%20%3D5%5E%7B%285%2F6%29%7D)
Step-by-step explanation:
The rules of exponents apply, even when they are fractional exponents:
![a^b\cdot a^c=a^{b+c}\\\\\sqrt[b]{x^a}=x^{(a/b)}](https://tex.z-dn.net/?f=a%5Eb%5Ccdot%20a%5Ec%3Da%5E%7Bb%2Bc%7D%5C%5C%5C%5C%5Csqrt%5Bb%5D%7Bx%5Ea%7D%3Dx%5E%7B%28a%2Fb%29%7D)
Y = mx + b. This linear graph passes through A(0,50) and B(10,51)
m = (y₂-y₁)/(x₂-x₁)
m= (51-50)/10-0)
m=(1)(10)
y = (1/x) + b. To find b, you plugin the coordinates of either A or B,
say A(0,50):
50 = (1/10).(0) + b
50 = 0+b and b= 51
Hence the equation is y =0.1x + 50
Amy is constructing an equilateral triangle. it's she joins the centers of the 2 circles to the point of intersection she will be done
option a
Answer:
a) 625; 625; right triangle
b) 205; 256; obtuse triangle
Step-by-step explanation:
The squares are values found in your memory or using a calculator. It is straightforward addition to find their sum.
<h3>left side</h3>
7² +24² = 49 +576 = 625
25² = 625
The sum of the squares of the short sides is the square of the long side, so this is a right triangle.
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<h3>right side</h3>
6² +13² = 36 +169 = 205
16² = 256
The long side is longer than is needed to form a right triangle, so the largest angle is more than 90°. This is an <em>obtuse triangle</em> (as shown).