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Wewaii [24]
2 years ago
11

Distance between parallel lines y=3x+10 and y=3x-20

Mathematics
1 answer:
Alecsey [184]2 years ago
4 0

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

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3 years ago
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Bezzdna [24]
To do this, we must set up ratios:
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\frac{2.30}{250g}  \\  \frac{0.0092}{1g}  \\ 0.0092/g
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Option Two:
\frac{3.40}{400g}  \\  \frac{0.0085}{1g} \\ 0.0085/g
The second option costs only $0.0085/gram (cheaper than option one)!
Option Three: 
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\frac{5.65}{1000g} \\  \frac{0.00565}{1g}  \\ 0.00565/g
The third option costs $0.00565/gram.

Therefore, option three is the cheapest! 

Hope this helps!
4 0
3 years ago
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Lady_Fox [76]

Answer:

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Step-by-step explanation:

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8 0
1 year ago
Which number line shows -4 , 1,1 and 2 correctly plotted
Colt1911 [192]

Answer:

C

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6 0
2 years ago
What is the area of this polygon?
elena55 [62]
A= 192 cm squared
Why?
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3 0
2 years ago
Read 2 more answers
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