All categories

3 years ago

each month for 7 months, samuel mwos 3 lawns. How many more lawns does he need to mow before he has mowed 29 laws?

Mathematics

2 answers:

ira [324]3 years ago

6 0

He needs to mow 8 more lawns

Sonbull [250]3 years ago

5 0

So you need to get to 29 lawns right? So 29 is a prime number and doesn't have three as a common factor. So you have to get down to the very last bit on how often he mows lawns in the seven months. 7/3 does that, it's not precise but it's a great estimation.

2.333=7/3

So every 2.33... months he mows a lawn. So what's 3's closest factor to 29? 27. So now do 7*9 as in the months and stuff. You get 27, already 27 months off the bat. Now then do 2.33...*2=4.66 months extra.

Here it is, just in case you don't want to read this all.

7/3=2.33...

7*9=27

29-27=2 2*2.33...=4.66+27

31.66 more months

You might be interested in

PLEASE HELP:) :( <br> What is the area of this Polygon? <br> Enter your answer in the box

BaLLatris [955]

7 x 5 = 35

1/2(7) x 2
3.5 x 2
7

35 + 7 = 42 Units squared

6 0

3 years ago

I need to find the angle of a sector of a circle when the arc length is 9pi/8 and the radius is 4.5, please help me!!

Sloan [31]

Answer:

Step-by-step explanation:

jr bacon cheese burger

3 0

3 years ago

What is 60/ 480 ? without calculator

romanna [79]

Answer:

1/8

Step-by-step explanation:

You must divide by common multipliers. so you can first divide the numerator and denominator by 10, which would make it 6/48, and then do that again with 6. Which then would give you the answer of 1/8.

4 0

3 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago

The area of a rectangular concrete patio is 70 square meters. the perimeter is 34 meters. what are the dimensions of the patio?

Finger [1]

A = L * W
A = 70

70 = L * W

P = 2(L + W)
P = 34

34 = 2(L + W)
34/2 = L + W
17 = L + W
17 - W = L

70 = L * W
L = 17 - W

70 = W(17 - W)
70 = -W^2 + 17W
W^2 - 17W + 70 = 0
(W - 10)(W - 7) = 0

W - 10 = 0 L = 17 - 10
W = 10 L = 7

W - 7 = 0 L = 17 - 7
W = 7 L = 10

so either the width is 10 meters and the length is 7 meters OR the width is 7 meters and the length is 10 meters

5 0

3 years ago