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lisabon 2012 [21]

2 years ago

7

Simplify your answer and write it as a proper fraction,improper fraction,or interger

1 answer:

devlian [24]2 years ago

4 0

Answer:

2

Step-by-step explanation:

Take any 2 points on the graph,

(50, 10) & (90, 90)

Use the slope formula:

$\frac{y2-y1}{x2-x1}$

= (90-10)/(90-50)

= (80)/(40)

= 2

Hence, the slope is 2.

<em>Feel free to mark this as brainliest! :D</em>

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Carl borrowed $7 for lunches during one week $8 for lunches during the next week. How much money did Carl borrow?

frez [133]

Answer:

Step-by-step explanation: quit

5 0

2 years ago

What would the answer be

Hoochie [10]

Answer:

B.

Step-by-step explanation:

process of elimination. the red dot is not a 1/4 of the number of lines, so it cant be 12.25, 13.625 is impossible because it has a value less than 13, and 12.625 is impossible as well because it has a value less than 12.5 therefore 12.375 is the best answer, and the only correct answer

4 0

2 years ago

How wide is a rectangular table with a length of 2/3 yard yard and an area of 1/2 square yard?

mylen [45]

<span>a = Lw
---
1/2 = (2/3)w
w = (1/2)(3/2)
---
w = 3/4 yard</span>

5 0

2 years ago

Pls answer with explanation!

patriot [66]

Answer:

3,750 cars.

Step-by-step explanation:

We are given that the equation:

$y=9000-2.4x$

Models the relationsip between <em>y</em>, the number of unfilled seats in the stadium, and <em>x</em>, the number of cars in the parking lot.

We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.

When there are no unfilled seats in the stadium, <em>y</em> = 0. Thus:

$0=9000-2.4x$

Solve for <em>x</em>. Subtract 9000 from both sides:

$-2.4x=-9000$

Divide both sides by -2.4:

$x=3750$

So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.

4 0

2 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

If

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

2 years ago