<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
Answer:
-8
Step-by-step explanation:
So first off, x is 2-4. So that's the default. It would be -2. If you multiply -2 by 2, it is -4.
Answer:
c. 250
Step-by-step explanation:
Arrange them first
4,5,5,6,10,11,12,13
These are 8 numbers.we will divide the sum of middle 2 numbees on 2.
6+10=16÷2
8..median
