Parallelograms, rectangles, rhombus, or square
Answer:
35% of $64.99=35/100 of 64.990=0.35×64.99=$22.7465
DISCOUNTED PRICE=$64.99-$22.7465=$42.2435
PLEASE GIVE BRAINLIEST
One application of volume is determining the density of an object. Assume the object is made of a pure element (eg: gold). If we know the volume (v) of the object, and we know the mass (m), then we can use the formula D = m/v to figure out the density D. Knowing the volume is also handy to determine if the object can fit into a larger space or not. Another application is figuring out how much water is needed to fill up the inner space of the 3D solid (assuming it's hollow on the inside).
The surface area is handy to figure out how much material is needed to cover the outer surface. This material can be paint, paper, metal sheets, or whatever you can think of really. A good example is wrapping a present and the assumption is that there is no overlap.
Answer:
The equivalent expression to the given expression is ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Step-by-step explanation:
The given expression is ![\sqrt[3]{32x^8y^{10}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D)
To find the equivalent expression:
![\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D%2832x%5E8y%5E%7B10%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We may write the above expression as below:
(using square root properties)
![=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y})](https://tex.z-dn.net/?f=%3D%282%5Csqrt%5B3%5D%7B4%7D%29%28x%5E2%5Csqrt%5B3%5D%7Bx%5E2%7D%29%28y%5E3%5Csqrt%5B3%5D%7By%7D%29)
(combining the like terms and doing multiplication )
![=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Therefore
Therefore the equivalent expression to the given expression is
