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Sergeu [11.5K]
3 years ago
15

What is the constant of proportionality in the equation y=2/3x

Mathematics
2 answers:
Elina [12.6K]3 years ago
7 0

Answer:

\frac{2}{3}.

Step-by-step explanation:

We have been given an equation y=\frac{2}{3}x. We are asked to find the constant of proportionality.

We know that two directly proportional quantities are in form y=kx, where y is directly proportional to x and k is the constant of proportionality.

Upon looking at our given equation, we can see that k=\frac{2}{3}, therefore, the constant of proportionality is \frac{2}{3} for our given equation.

Alexandra [31]3 years ago
6 0
2/3x no y intercept


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If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?
eduard

Answer:

cos(\alpha+\beta)=-\frac{84}{85}

Step-by-step explanation:

we know that

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

Remember the identity

cos^{2} (x)+sin^2(x)=1

step 1

Find the value of sin(\alpha)

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

cos(\alpha)=-\frac{8}{17}

Find the value of sine

cos^{2} (\alpha)+sin^2(\alpha)=1

substitute

(-\frac{8}{17})^{2}+sin^2(\alpha)=1

sin^2(\alpha)=1-\frac{64}{289}

sin^2(\alpha)=\frac{225}{289}

sin(\alpha)=-\frac{15}{17}

step 2

Find the value of cos(\beta)

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

sin(\beta)=-\frac{4}{5}

Find the value of cosine

cos^{2} (\beta)+sin^2(\beta)=1

substitute

(-\frac{4}{5})^{2}+cos^2(\beta)=1

cos^2(\beta)=1-\frac{16}{25}

cos^2(\beta)=\frac{9}{25}

cos(\beta)=\frac{3}{5}

step 3

Find cos⁡ (α + β)

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

we have

cos(\alpha)=-\frac{8}{17}

sin(\alpha)=-\frac{15}{17}

sin(\beta)=-\frac{4}{5}

cos(\beta)=\frac{3}{5}

substitute

cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})

cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}

cos(\alpha+\beta)=-\frac{84}{85}

4 0
3 years ago
Identify the lateral area and surface area of a regular square pyramid with base edge length 5 in. and slant height 9 in.
Galina-37 [17]
Note that a squared pyramid has a square base & 4 equal triangles.
To find the lateral the lateral area you calculate the area of the 4 equal triangles  and to find the surface area (total Area) you add the area of the base:

Area of each triangle = side (5) x slant (9) and you divide by 2

==>Aera of 1 triangle = (9x5)/2 = 45/2 & for the 4 triangles

Lateral area = (45/2) x 4 = 90 in²

Now the base area (square) = 5 x 5= 25 in²

so the surface area = 90+25 = 115 in² (answer a)
7 0
2 years ago
Factor the expression. 35x-28xy=
zalisa [80]

Answer:

7x(5-4y)

Step-by-step explanation:

35x-28xy

7x(5-4y)

4 0
2 years ago
Read 2 more answers
Help asap please!!<br> Find the measure of y.<br> A. 43<br> B. 53<br> C. 90<br> D. 47
Amiraneli [1.4K]

Answer:

y=43

Step-by-step explanation:

y=2(90-46)/2

y=43

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5 0
2 years ago
Please help me with number 1 please help ???
stira [4]

Answer:

mean: 26

median: 28

mode: 28

range:19

Step-by-step explanation:

hipe this helped hun

3 0
2 years ago
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