Answer:
26 ft square by 13 ft high
Step-by-step explanation:
The tank will have minimum surface area when opposite sides have the same total area as the square bottom. That is, their height is half their width. This makes the tank half a cube. Said cube would have a volume of ...
2·(8788 ft^3) = (26 ft)^3
The square bottom of the tank is 26 ft square, and its height is 13 ft.
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<em>Solution using derivatives</em>
If x is the side length of the square bottom, the height is 8788/x^2 and the area is ...
x^2 + 4x(8788/x^2) = x^2 +35152/x
The derivative of this is zero when area is minimized:
2x -35152/x^2 = 0
x^3 = 17576 = 26^3 . . . . . multiply by x^2/2, add 17576
x = 26
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As the attached graph shows, a graphing calculator can also provide the solution.
Answer:
1. 32, 12
2. Enlargement
Step-by-step explanation:
Enlarged by a scale factor of 4
(Multiply all points by 4)
8 x 4 = 32
3 x 4 = 12
It is an enlargement because the points are larger than before.
Part a: Option D 18 feet per second
Part b: increasing
Solution:
Height 
Part a: To find the average rate of change for h(t) between t = 0 and t = 2.
Substitute t = 0 in h(t).

h(0) = 3
Substitute t = 2 in h(t).
h(2) = 39
Average rate of change formula:

Here, a = 0 and b = 2.



= 18
Average rate of change = 18 feet per second
Option D is the correct answer.
Part b:
This means height of the ball is increasing for 0 < x < 2.
1angle = 90
4 angles =360
the answer is false
Step-by-step explanation:
5 + d > 5 - d
5 + d + d > 5
5 + 2d > 5
2d > 5 - 5
2d > 0
d > 0 ÷ 2
d > 0