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vlabodo [156]
3 years ago
13

Solve the equation (6+2i)(3i)

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0
3i(6+2i) = 18i+6i^2 = 6i(3+i) if i is a variable

3i(6+2i) = 18i+6i^2=18i+6(-1) = -6+18i = 6(-1+3i) if i is the imaginary unit defined by i²=-1
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Which could be the entire interval over which the function,
Marrrta [24]

Answer:

(-2, 1)

Step-by-step explanation:

Hi Juliadayx! How are you?

Well, maybe you already heard about the domain and the range of a function.  

The domain is the set of values that the independent variable can take (usually referred to as the letter "x"), while the range is the set of values that the dependent variable takes, which is called f(x) or function of x.

In this case, the exercise asks you to evaluate for which values of “x” (right column of the table), the function “f(x)” takes positive values (left column of the table), the positive values also include zero. And in this case you can see that the function f(x) is only positive for the values of "x": -2, -1, 0 and 1. Therefore, the answer is the entire interval (-2, 1).

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3 0
3 years ago
Help please hurry need help
Misha Larkins [42]

Answer:

1: D

2: B

3: y=-4x+22

4: y=-8x+26

Step-by-step explanation:

1: Parallel lines have the same slope, and the only one with a slope of 3x is D

2: Perpendicular lines have an opposite slope, so a line with a slope of -1/2 would be 2, so you just flip the number and add or take away a negative sign, depending on the original slope

3: Like I said before, perpendicular lines have an opposite slope, so the slope would be -4. After you've figured that out, you just plug in the numbers given to you (and remember, x is first, y is last)

Plug in: 6=-4(4)+b

You would then solve for b.

6=-16+b

22=b

Then plug that into y=mx+b, with m being the slope (-4) and b being the y intercept (22)

4: The process for finding parallel and perpendicular lines is very similar, except you don't have to change the slope.

Plug in: 10=-8(2)-b

10=-16+b

26=b

Again, plug that into the equation y=mx+b

Hope I could be of help! Sorry if it doesn't make sense, this is my first time on this website.

5 0
3 years ago
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