Answer:
Option B k > 0
Step-by-step explanation:
we know that
Observing the graph
The slope of the line is positive
The y-intercept is negative
we have
![3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)](https://tex.z-dn.net/?f=3y-2x%3Dk%285x-4%29%2B6%5C%5C%20%5C%5C3y%3D5kx-4k%2B6%2B2x%5C%5C%20%5C%5C3y%3D%5B5k%2B2%5Dx%2B%286-4k%29%5C%5C%20%5C%5Cy%3D%5Cfrac%7B1%7D%7B3%7D%5B5k%2B2%5Dx%2B%282-%5Cfrac%7B4%7D%7B3%7Dk%29)
The slope of the line is equal to
![m=\frac{1}{3}[5k+2]](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B1%7D%7B3%7D%5B5k%2B2%5D)
Remember that the slope must be positive
so

The value of k is greater than -2/5
Analyze the y-intercept

1.5 is greater than zero
so
the solution for k is the interval ------> (1.5,∞)
therefore
must be true
k > 0
Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

In the given case, you have:
A = 4
T = 3π/4
b = -3
By replacing you obtain:

Hence, the answer is:
f(x) = 4cos(8/3 x) - 3
Three would be your answer :)
Step-by-step explanation:
hand towel is $5
bath towel is $9