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Lubov Fominskaja [6]
3 years ago
7

1. What is the prime factorization of 28?

Mathematics
1 answer:
lana66690 [7]3 years ago
5 0
28 = 2 to the power of 8 x 7 or

28= 4 x 7= 2 x 2 x 7

Both the same
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Simplify to create an equivalent expression.<br> 10+4(-8 q-4)}10+4(−8 q−4)
ale4655 [162]

Answer:: -0.3125 + q + 0.5

If our equation is: 10 + 4(-8q - 4)  then we can simplify it in the next way:

first distribute the 4 with the content in the parentheses.

10 + 4(-8q - 4) = 10 -(8*4)q - 4*4 = 10 - 16 -32q = -6 -32q

now dependes on you, i like to put the negative sign outside  a parenthesis:

-(32q + 6)

and this is your simplified equation, just give solve it. <u>HOPES </u><u>THIS HELPS</u>

3 0
3 years ago
Read 2 more answers
It takes 72 pounds of seed to completely plant an 11-acre field. How many pounds of seed are needed per acre? poundsperacre
yarga [219]

Answer:

6.54lbs per acre

Step-by-step explanation:

72/11

7 0
3 years ago
I Have No Idea How To Do This, Does Anyone Have An Idea To Calculate This?
Natasha2012 [34]

Answer:

AOB = 55°

BOC = 87°

COD = 130°

AOD = 88°

Step-by-step explanation:

AOB = a°

= 55°

BOC = b°

= 87°

COD = c°

= 130°

AOD = 360°-AOB-BOC-COD

= 360°- a° - b° - c°

= 360° - 55° - 87° - 130°

= 88°

(Correct me if i am wrong)

8 0
4 years ago
Read 2 more answers
8. A concert charges $10 for each adult ticket and $5 for each child ticket. Sunday, the park collected a total of $1,750
Sphinxa [80]

Do you need both of the equations or just the entire solution?

6 0
3 years ago
Select the correct answer. Which matrix represents this system of equations? -2y + 7z = 10 9x + 5y = 1 2x + z = -5
Stells [14]

Answer:

In matrix form this can be represented as

\left[\begin{array}{ccc}0&-2&7\\0&5&0\\2&0&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}10\\1\\5\end{array}\right]



Step-by-step explanation:

The given equations are

-2y + 7z = 10

9x + 5y = 1

2x + z = -5

Which can be written as

0x+-2y + 7z = 10

9x + 5y+0z = 1

2x +0y+ z = -5

In matrix form this can be represented as

\left[\begin{array}{ccc}0&-2&7\\0&5&0\\2&0&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}10\\1\\5\end{array}\right]



When we multiply the above matrices we get the given set of equations.

In multiplying the matrices we check the no of columns of the first matrix and the number of rows of the second matrix. If they are equal ( as in this case they are 3) then the matrices can be multiplied .

The answer has the number of rows equal to the number of rows of the first matrix and the number of columns equal to the number of columns of the second matrix which is true in this case.

4 0
3 years ago
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