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kvv77 [185]
2 years ago
10

Question Progress

Mathematics
1 answer:
KIM [24]2 years ago
4 0

Answer:

4 7 12. 19 28 then and is 39

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Please help asap!<br><br>the problem is in the picture
ladessa [460]

Given:

AB=6\ BC=r,\ CD=r,\ AD=12.

To find:

The value of r.

Solution:

We have,

AB=6\ BC=r,\ CD=r,\ AD=12.

We know that the radius is perpendicular to the tangent at the point of tangency

AD is the tangent and CD is the radius. So, CD is perpendicular to AD at point D, i.e., m\angle D=90^\circ.

Using Pythagoras theorem, we get

AC^2=AD^2+CD^2

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12r=144+r^2-36-r^2

On further simplification, we get

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Therefore, the value of r is 9.

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