PLEASE HELP ): Which ordered pairs are on the line 4x-3y=8

Evaluating express<br> 6<br> Evaluate 13 + - when y = 6.<br> y

Step2247 [10]

Step-by-step explanation:

how i think this question is

13+ -y

y=6

= 13 + -6

=7

therefore the answer is 7

7 0

3 years ago

Consider the following 8 numbers, where one labelled x is unknown. 42, 47, 5, x , 18, 12, 50, 1 Given that the range of the numb

Dahasolnce [82]

<h3>The two possible values for x are x = 60 and x = -9</h3>

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Explanation:

Let's assume that x is the largest value of the list. If so then x = 60 because

range = max - min

range = x - 1

range = 60-1

range = 59

Effectively, you work backwards to go from a range of 59 to have x = 60 as the max.

So x = 60 is one possible value. We can't have x any larger or the range would be larger.

But we can have x be smaller. Specifically, it would be the min of the list. If negative x values are allowed, then x = -9 is the other possible x value

Here's why

range = max - min

range = 50 - x

range = 50 - (-9)

range = 50+9

range = 59

3 0

3 years ago

11

drek231 [11]

Answer:

sub to graec franz

Step-by-step explanation:

6.72 4893,.43

7 0

3 years ago

SURFACE AREAS - PYRAMIDS?

Bond [772]

The total surface area consists of the base area and the surface area (the area of all lateral faces). The base is a hexagon with side a=3 cm.

$A_{hexagon}=6A_{triangle}=6\cdot \dfrac{1}{2} \cdot \dfrac{a^2\sqrt{3}}{4} =\dfrac{3}{4} \cdot 3^2\cdot \sqrt{3}=\dfrac{27\sqrt{3}}{4}$ sq. cm.

Each lateral face is an isosceles triangle with height h=12 cm and base a=3 cm. The area of one such lateral triangle is

$A_{lateral}=\dfrac{1}{2}\cdot h\cdot a= \dfrac{1}{2}\cdot 12\cdot 3=18$ sq. cm.

Then the total surface area is:

$A_{total}= \dfrac{27\sqrt{3}}{4} +6\cdot 18=\dfrac{27\sqrt{3}}{4} +108=11.7+108=119.7$ sq. cm.

Answer: 119.7 sq. cm.

7 0

4 years ago

The number of apples in the box was less than 80. It is possible to divide all the apples evenly among 3, 4, and 5 children. How

ANEK [815]

Answer:

60 apples

Step-by-step explanation:

There are some number of apples in the box which is less than 80.

Now, it is given in the condition that all the apples can be divided evenly among 3, 4, and 5 children.

Therefore, the number of apples is a common multiple of 3, 4, and 5 which is less than 80.

Now, multiples of 3 less than 80 are 78, 75, 72, 69, 66, 63, 60, etc.

And, multiples of 4 less than 80 are 76, 72, 68, 64, 60, 56, etc.

Again, multiples of 5 less than 80 are 75, 70, 65, 60, 55, etc.

Therefore, the common multiple less than 80 is 60.

Hence, there were 60 apples in the box. (Answer)

6 0

4 years ago