Question

A sample of a hydrated salt weighing 1.167 g is heated until no more water is given off. The mass of the anhydrous salt was 0.6298
a) What is the mass of water lost by the sample?

Answer 1

"0.538 g" would be the mass of the water.

Given values are:

Hydrated salt,

• 1.167 g

Anhydrous salt,

• 0.629 g

→ The mass of water lost by the salt will be:

= $Hydrated \ salt - Anhydrous \ salt$

By substituting the given values, we get\

= $1.167-0.629$

= $0.538 \ g$

Thus the above answer is appropriate.

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Answer 2

Answer:

The mass of water lost is:

(2) = 1 − 2 = 1.167 − 0.629 = 0.538

The mass % of water in the hydrated salt is:

(2) =

(2)

1

=

0.538

1.167 ∙ 100% = 46.0 %

Answer: 0.538 g; 46.0 %