Question

What is the maximum mass of pure gold that could be extracted from 3.0kg of calaverite, a gold ore with the chemical formula AuTe2? Be sure your answer has a unit symbol, if necessary, and is rounded to 2 significant digits.

Answer 1

Answer:

1.3 × 10³ g

Explanation:

Step 1: Convert the mass of calaverite to grams

We will use the relationship 1 kg = 1,000 g.

$3.0kg \times \frac{1,000g}{1kg} = 3.0 \times 10^{3} g$

Step 2: Establish the appropriate mass ratio

The mass ratio of AuTe₂ to Au is 452.17:196.97.

Step 3: Calculate the maximum mass of pure gold that can be obtained from 3.0 × 10³ g of calaverite

$3.0 \times 10^{3} g Calaverite \times \frac{196.97gAu}{452.17gCalaverite} = 1.3 \times 10^{3} gAu$