Answer:
im pretty sure the answer is d
Step-by-step explanation:
if the circumference of the shield is 100.48inches, nits radius is 16 inches and the area of the front of the shield is about 803.84 square inches.
proof
circumference = 2x r x Pi implies r =circumference / 2Pi=100.48/2x3.14=16
area = Pi x r²=3.14 x 16²=804.84
Well you can either think of actually dividing the fraction or reduce to lowest forms which is 1/2. then from 1/2 you can either divide that or just say it is .5.
Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR
Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)
Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)
Have an awesome day! :)
Answer:
what is the question then
Step-by-step explanation:
