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kaheart [24]
3 years ago
5

What is the square root of 108 divided by the square root of 2q^6?? I really REALLY need the answer fast!

Mathematics
2 answers:
dedylja [7]3 years ago
8 0
\sqrt{108}:\sqrt{2q^6}=\sqrt{\frac{108}{2q^{3\times2}}}=\sqrt{\frac{54}{(q^3)^2}}=\sqrt{\frac{9\times6}{(q^3)^2}}=\frac{\sqrt{9\times6}}{\sqrt{(q^3)^2}}=\frac{\sqrt9\times\sqrt6}{q^3}=\frac{3\sqrt6}{q^3}
Kruka [31]3 years ago
4 0
Answer in attachment below.... Open it up in a new window to see it in full.

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Based on the information given, the angle will be calculated thus:

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