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Furkat [3]
3 years ago
8

A new car worth ​$18 comma 000 is depreciating in value by ​$3 comma 000 per year. after how many years will the​ car's value be

​$3 comma 000​?
Mathematics
1 answer:
ehidna [41]3 years ago
8 0
Its 5 years
worth = 18000
depriciation per year= 3
in 5 year car value= 18000 minus 5×3000= 3000
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Novosadov [1.4K]
-26+75=43 hope this helps


3 0
4 years ago
Lacy opened a savings account and deposited $100. The account earns 6% interest compounded monthly if she wants to use the money
Dafna11 [192]

Answer:

Future Value= $112.72

Step-by-step explanation:

Giving the following information:

Initial deposit (PV)= $100

Number of periods (n)= 2*12= 24 months

Interest rate (i)= 0.06/12= 0.005

<u>To calculate the future value (FV), we need to use the following formula:</u>

FV= PV*(1 + i)^n

FV= 100*(1.005^24)

FV= $112.72

5 0
3 years ago
Use the graph to find the possible value for X such that f(x) =10
Dafna1 [17]

Answer:

15 is right ans

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
D<br> B<br> 3x43<br> IC<br> 4x+2<br> Determine the value of mZDCB.
Studentka2010 [4]

Step-by-step explanation:

3x+3² , you might want a second opinion I am no good at math but I tried to work it out to see if I would get it right so don't quote me on this and put it down for an answer get a second opinion please

7 0
3 years ago
The graph below shows the value of Edna's profits f(t), in dollars, after t months:
umka21 [38]
Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), x=6 and x=18 are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
x=6
x-6=0
x=18
x-18=0

(x-6)(x-18)=x^{2}-6x-18x+108
=x^{2}-24x+108

Now that we have our quadratic function, we are going to use the average formula: m= \frac{f(9)-f(3)}{9-3}
where
f(9) is the function evaluated at  the <span>9th month
</span>f(3) is the function evaluated at the 3rd month 

m= \frac{f(9)-f(3)}{9-3}
m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}
m= \frac{-27-45}{6}
m= \frac{-72}{6}
m=-12

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>

6 0
3 years ago
Read 2 more answers
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