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LUCKY_DIMON [66]
3 years ago
8

Choose the number sentence that illustrates the distributive property of multiplication over addition.

Mathematics
1 answer:
Ratling [72]3 years ago
6 0

Answer:

One number sentence shows the distributive property of multiplication over addition. ... (5 + 4) × 3 = (5 × 3) + (4 × 3) is an example of the distributive property. (5 − 4) × 3 = 1 × 3. 1 × 3 is not equal to (1 × 3) − (1 × 3).

Step-by-step explanation:

A

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Girardo is using the model below to solve the equation 3x+1=4x+(-4)
V125BC [204]

Answer:

x=5

Step-by-step explanation:

3x+1= 4x+(-4)

-4×+1= -4x-1 combine like terms

-1x= -5 divided by -1

x= 5

5 0
2 years ago
I bet no body can do it
strojnjashka [21]

You are right, good luck
3 0
3 years ago
What is the coefficient in the expression 40a-61=17
zepelin [54]

Answer:

a = 1.95

Step-by-step explanation:

40a - 61 = 17

40a - 61 + 61 = 17 + 61

40a = 78

40a / 40 = 78 / 40

a = 1.95

5 0
3 years ago
What is the simplified form of<br> (4ab)^2
Alex
Use\ (a\cdot b)^n=a^nb^n\\-----------------\\\\(4ab)^2=4^2a^2b^2=\huge\boxed{16a^2b^2}
7 0
3 years ago
Can someone please help me with this last one. I am totally lost and don’t understand
Ad libitum [116K]

Answer:

g(-4) = -1

g(-1) = -1

g(1) = 3

Explanation:

If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.

As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.

It is a coincidence that g(-1) = -1.

Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.

We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3

4 0
3 years ago
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