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Serjik [45]
3 years ago
11

Please help 15 POINTS

Mathematics
2 answers:
irga5000 [103]3 years ago
7 0
Answer: 4 4/5

Ya ok ya ok
Sedaia [141]3 years ago
3 0

Answer:

the answer in mixed number is 4whole 4/5

4  \frac{4}{5}

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Find the number of integral solutions of x+y +z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and<br> z ≥ 3.
SashulF [63]

There are 59 integer solutions

Such questions are best solved by writing cases and calculating the total number of cases. So beginning with

1)  x = -3. The possible combinations are as follows:-

-3 2 13

-3 3 12

-3 4 11

-3 5 10

-3 6 9

-3 7 8

-3 8 7

-3 9 6

-3 10 5

-3 11 4

10 combinations

2) x = -2

-2 2 12

through

-2 11 3

10 combinations

3) x = -1

-1 2 11

through

-1 10 3

9 combinations

4) x = 0

0 2 10

through

0 9 3

8 combinations

as we can see from the pattern at x =1  we get 7 combinations, at x =2  we get 6 combinations, at x=3 we get 5 combinations and at x =4  we get 5 combinations.

Thus total number of combinations 4+5+6+7+8+9+10+10 = 59 integer solution.

Learn more about combinations here :

brainly.com/question/13387529

#SPJ1

5 0
2 years ago
On what interval(s) is the graph decreasing? - use interval notation
Anna [14]
The function is decreasing from -6 to -3, that is, on the interval (-6,-3), and again on the interval (1, infinity).  

The function is increasing on (-3,1).

No local or absolute minimum.

(1,4) is an absolute max.
6 0
4 years ago
490 as a product of its prime factors
Katena32 [7]

Answer:

2×5×7²

Step-by-step explanation:

You will start by using the factor tree.

490

^

2 245

^

5 49

^

7 7

8 0
3 years ago
How do I find the answer?
svlad2 [7]

Answer:

do you still need help

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
The solution to a system of linear equations is (-3,-3) Which system of linear equations has this point as its solution? x -5y=-
Ann [662]

Answer:

x-5y=12 and 3x+2y=-15

Step-by-step explanation:

The first system is

x-5y=-12 and 3x+2y=-15

We substitute x=-3 and y=-3

-3-5*-3=12\ne-12 and 3*-3+2*-3=-15

Both equations are not satisfied

The next system is

x-5y=12 and 3x+2y=-15

We substitute x=-3 and y=-3

-3-5*-3=12 and 3*-3+2*-3=-15\ne15

Both equations are satisfied

The next system is

x-5y=-12 and 3x+2y=15

We substitute x=-3 and y=-3

-3-5*-3=12\ne12 and 3*-3+2*-3=-15

Both equations are not satisfied

The next system is

x-5y=12 and 3x+2y=15

We substitute x=-3 and y=-3

-3-5*-3=12\ne-12 and 3*-3+2*-3=-15

Both equations are  not satisfied

6 0
4 years ago
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