Relate speed, velocity, and acceleration to objects in motion.
1 answer:
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Answer:
Mininmum acceleration required =
Explanation:
Given,
Lift off speed = 125km/hr.
We know km/hr conversion factor to m/s is ,
Therefore,
Lift off speed required = m/s
Lift off speed required = 34.72222 m/s
Length of Takeoff Run given = 220 m.
So,
the flight needs to achieve its takeoff speed at a constant acceleration before it reaches the end of the 220 m runway.
Consider the formula from kinematics,
,
where,
v - final velocity of particle,
u - initial velocity of particle
a - the constant acceleration at which the particle is moving with
s - distance travelled by particle
So at minimum acceleration,it reaches the takeoff speed at the end of the runway.
Therefore in the formula,
we use, v = Lift off speed = 34.72222 m/s;
u = 0 m/s (plane starts from rest);
a = minimum acceleration of the plane
s = 220 m;
Substituting these values in the formula, we get,
a =
a = .
Therefore,the minimum acceleration of the plane required = .
Answer:
Explanation:
The ant , at some point of time will be standing on the crest of moving wave passing under its feet . At that position the downward acceleration of the ant will be equal to its weight . Hence it will feel weightlessness . So at that time
Acceleration = g
Acceleration at the top position = ω²A where ω is angular velocity and A is amplitude of vibration ( transverse ) of crest .
ω =2 π n where n is frequency of transverse vibration of particles. This angular frequency will be equal to angular frequency of wave travelling on the rope .
frequency of travelling wave
n.=
ω =2 π x
ω² = 4π² x T/γ²μ}
For weightlessness
ω² A = g
A= g x γ²μ / 4π² T