Two descriptions about physical quantities are given below:

Because force always has a direction, it always works towards or against something.

you might know that force,
is rate of change of momentum i.e

force = m (v-u)/t
= (mv - mu )/ t

as we know momentum is a vector quantity so, the rate of change of momentum i.e Force would also be a vector quantity.

momentum = mass × velocity

velocity has a direction so,
momentum has also got a direction.
so, momentum is also a vector quantity.

3 0

3 years ago

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Read this article discussing the amount of time that people of various ages and education levels report spending on different te

iVinArrow [24]

The article is not found here but surveys are important because they are representative samples of a population.

<h3>What is a survey?</h3>

A survey is a useful tool based on population samples, which is used to make statistical analyses in a given investigation.

Differences in surveys are generally due to small sample sizes, which may lead to errors in the analysis of data.

In conclusion, the article is not found here but surveys are important because they are representative samples of a population.

Learn more about surveys here:

brainly.com/question/13624055

#SPJ1

7 0

1 year ago

A swimming pool is 50 ft wide and 100 ft long and its bottom is an inclined plane, the shallow end having a depth of 4 ft and th

Nina [5.8K]

Explanation:

We define force as the product of mass and acceleration.

F = ma

It means that the object has zero net force when it is in rest state or it when it has no acceleration. However in the case of liquids. just like the above mentioned case, the water is at rest but it is still exerting a pressure on the walls of the swimming pool. That pressure exerted by the liquids in their rest state is known as hydro static force.

Given Data:

Width of the pool = w = 50 ft

length of the pool = l= 100 ft

Depth of the shallow end = h(s) = 4 ft

Depth of the deep end = h(d) = 10 ft.

weight density = ρg = 62.5 lb/ft

Solution:

a) Force on a shallow end:

$F = \frac{pgwh}{2} (2x_{1}+h)$

$F = \frac{(62.5)(50)(4)}{2}(2(0)+4)$

$F = 25000 lb$

b) Force on deep end:

$F = \frac{pgwh}{2} (2x_{1}+h)$

$F = \frac{(62.5)(50)(10)}{2} (2(0)+10)$

$F = 187500 lb$

c) Force on one of the sides:

As it is mentioned in the question that the bottom of the swimming pool is an inclined plane so sum of the forces on the rectangular part and triangular part will give us the force on one of the sides of the pool.

1) Force on the Rectangular part:

$F = \frac{pg(l.h)}{2}(2(x_{1} )+ h)$