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3 years ago

Which form of electromagnetic radiation with a relatively high amount of energy is used to sanitize lab goggles?

Physics

1 answer:

alexdok [17]3 years ago

5 0

Answer:

Gamma radiation.

Explanation:

Electromagnetic waves are waves produced with respect to the interaction of electric field and magnetic field. They can be arranged with respect to their increasing or decreasing wavelength to form a pattern called electromagnetic spectrum.

Gamma radiation can be used for sterilization purpose due to the fact that it has a relatively high amount of energy, and do not produce any characteristic radiation.

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A 52 kg and a 95 kg skydiver jump from an airplane at an altitude of 4750 m, both falling in the pike position. Assume all value

Scilla [17]

Answer: 52 kg skydiver: 9.09 m/s and 522.55 s

95 kg skydiver: 12.3 m/s and 386.2 s

Explanation: Drag Force is an opposite force when an object is moving in a fluid.

For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.

Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:

$F_{G}=F_{D}$

$mg=\frac{1}{2}C \rho Av_{T}^{2}$

$v_{T}=\sqrt{\frac{2mg}{\rho CA} }$

where

m is mass in kg

g is acceleration due to gravitational force in m/s²

ρ is density of the fluid in kg/m³

C is drag coefficient

A is area of the object in the fluid in m²

Calculating:

The 52kg skydiver has terminal velocity of:

$v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }$

$v_{T}=$ 9.09

The 95kg skydiver's terminal velocity is

$v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }$

$v_{T}=$ 12.3

The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.

The time each one will reach the floor will be:

52 kg at 9.09 m/s:

$t=\frac{4750}{9.09}$

t = 522.5

95 kg at 12.3 m/s:

$t=\frac{4750}{12.3}$

t = 386.2

The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.

3 0

3 years ago

A wave has a wavelength of 125 meters is moving at a speed of 20 m/s. What is it’s frequency?

Ann [662]

Answer: 0.16Hz

Explanation:

Given that:

wavelength (λ) = 125 meters

speed (V) = 20 m/s

frequency (F) = ?

Recall that frequency is the number of cycles the wave complete in one second. And its value depends on the wavelength and speed of the wave.

So, apply the formula V = F λ

Make F the subject formula

F = V / λ

F = 20 m/s / 125 meters

F = 0.16 Hz

Thus, the frequency of the wave is 0.16 Hertz.

4 0

3 years ago

Planet with the most extreme temperature range

Leokris [45]

Answer:

Mercury

Explanation:

3 0

3 years ago

A trombone has a variable length. When a musician blows into the mouthpiece and causes air in the tube of the horn to vibrate, t

lana66690 [7]

Answer:

The frequency increases with a shorter horn (Option B).

Explanation:

The length of the horn determines the distance along which the wave travels; simply called the wavelength. Therefore, a short horn tube will produce a short wavelength and vice versa.

Sound waves have various characteristics that define pitches in musical instruments and these characteristics are interdependent on each other.

in this case, the frequency and the frequency and the wavelength are related.

The relationship between the wavelength and its frequency is given as:

c = f λ 

where 'c' is the speed of sound through the instrument; 'f ' is the frequency and 'λ' is the wavelength.

Let's assume that the speed at which the musician blows air into the mouthpiece remains constant, an increase in wavelength will cause a decrease in frequency. Conversely, as the tube of the horn becomes shorter the frequency increases.

6 0

3 years ago

When you skid to a stop on your bike, you can significantly heat the small patch of tire that rubs against the road surface. Sup

Wittaler [7]

Answer:

$W_f = 148.17J$

Explanation:

During the exchange of applied force, thermal energy is generated by the friction that exists between the ground and the tire.

Said force according to the statement is the reaction of half the force on the rear tire. In this way the normal force acted is,

$N=\frac{mg}{2} = \frac{90*9.8}{2} = 441N$

The work done is given by the friction force and the distance traveled,

$W_f = fd = \mu_k Nd$

Where $\mu_k [/ tex] is the coefficient of kinetic frictionN is the normal force previously found d is the distance traveled,Replacing,[tex]W_f = (0.80)(441)(0.42)$

The thermal energy released through the work done is,

$W_f = 148.17J$

3 0

4 years ago