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PIT_PIT [208]
3 years ago
13

The acceleration due to gravity of all objects in free fall is the same. Why, then, do some objects fall through the air at a di

fferent rate than others?​
Chemistry
1 answer:
kenny6666 [7]3 years ago
6 0

Answer:

Displacement. (I think)

Explanation:

When you observe both a bowling ball and a feather falling to the ground at the same time, you see that the feather falls much slower. This is because the feather displaces the air around it.

Look closer at the feather. Notice that all the feather is are fibers sprouting from the quill. The air moves through these fibers slower and displaces the air around them. this is what helps birds to fly and glide.

Now observe someone in a flight suit. A flight suit has a type of fabric webbing in-between the arms and legs of the wearer. This allows them to glide through the air (when they gain lift) because the higher surface area of a light material displaces the air around it.

Regards! (And sorry if I'm wrong!)

You might be interested in
What is not within the scope of chemistry
ankoles [38]

hello!

your answer will be

The origin of the matter does not usually fall into chemistry

have a goed day

5 0
4 years ago
Trichloroethylene, a widely used degreasing solvent for machine parts, is produced in a two-step reaction sequence. Ethylene is
solmaris [256]

Answer:

ΔH°C2H2Cl4(l) = -333,36 kJ/mol

ΔH°r₂ = -35,14 kJ/mol

Explanation:

The ΔH°r of the first reaction is:

ΔH°r = -385,76 kJ/mol = (ΔH°C2H2Cl4(l) + ΔH°H2(g)) - (ΔH°C2H4(g) + 2ΔHCl2 (g))

ΔH°H2(g) = 0 kJ/mol

ΔH°C2H4(g) = 52,4 kJ/mol

Δ°HCl2 (g) = 0 kJ/mol

Replacing:

ΔH°C2H2Cl4(l) = -385,76 kJ/mol + 52,4 kJ/mol = <em>-333,36 kJ/mol</em>

The standard heat of the second reaction is:

ΔH°r₂ = ΔH°C2HCl3(l) + ΔH°HCl(g) - ΔH°C2H2Cl4(l)

Where:

ΔH°C2HCl3(l) = -276,2 kJ/mol; ΔH°HCl(g) = -92,3 kJ/mol; ΔH°C2H2Cl4(l) = -333,36 kJ/mol

Replacing:

ΔH°r₂ = -276,2 kJ/mol -92,3 kJ/mol + 333,36 kJ/mol

<em>ΔH°r₂ = -35,14 kJ/mol</em>

<em></em>

I hope it helps!

4 0
3 years ago
CADMIUM SOLUBILITY AND pH Cadmium is a toxic metal. It can be removed from water by chemical precipitation of solid cadmium hydr
Serga [27]

Explanation:

It is known that,

      Molar mass of Cd = 112.41 g/mol

Standard concentration of Cd = 0.005 mg/L = 0.005 \times 10^{-3} g/L

Hence, we will calculate the molarity as follows.

        Molarity = \frac{0.005 \times 10^{-3}}{112.41} mol/L

                       = 4.45 \times 10^{-8} M

Equation for the reaction is as follows.

          Cd(OH)_{2} \rightleftharpoons Cd^{2+} + 2OH^{-}

         K_{sp} = [Cd^{2+}][OH^{-}]^{2}]

          2 \times 10^{-34} = 4.45 \times 10^{-8} \times [OH^{-}]^{2}

          [OH^{-}] = 6.7 \times 10^{-4} M

Also,

         [H^{+}] = \frac{10^{-14}}{[OH^{-}]}

                      = \frac{10^{-14}}{6.7 \times 10^{-4}}

                      = 1.49 \times 10^{-11} M

Relation between pH and concentration of hydrogen ions is as follows.

               pH = -log [H^{+}]

                     = -log (1.49 \times 10^{-11} M)

                     = 10.82

Thus, we can conclude that a minimum pH of 10.82 is necessary to reduce the dissolved cadmium ion concentration to the standard.

4 0
3 years ago
5.0 g of NaCl is dissolved in water, and the solution is brought to a final volume of 150 mL. What is the molarity of this solut
Ksju [112]

Answer:

Molarity is a sort of concentration for solutions. When you talk about it, means mols of solute, that are in 1000 ml of solution. The molarity at this is 0.57M

Explanation:

As you have the solution in a volume of 150ml with 5 g of solute, in 1000 ml how much solute, do u have? The answer is 33.333g so now, you have to take the molar mass of NaCl and get the mols. Mass/molar mass, you will get the moles, so 33,3333 g / 58,44 g/m is 0.570 moles. That's M

6 0
4 years ago
Plastic is used to cover the copper wire in the power codes of appliances because plastic differs from copper in _________
Nezavi [6.7K]

Answer:

in copper from different plastics because appliances of codes to power day in wire copper the cover to use to plastic

4 0
3 years ago
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