Answer : The correct option is, (D)
Solution :
Formula used :
where,
Q = heat released = -1300 J
m = mass of water = 40 g
c = specific heat of water =
= final temperature = ?
= initial temperature =
Now put all the given values in the above formula, we get the final temperature of water.
Therefore, the final temperature of the water is, 
Answer:
Explanation:
Cheese, Meat, dough, Sauce
<u>Answer:</u> The amount of heat released when 0.211 moles of
reacts is 554.8 kJ
<u>Explanation:</u>
The chemical equation for the reaction of
with oxygen gas follows:

The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(5\times \Delta H_f_{(B_2O_3(s))})+(9\times \Delta H_f_{(H_2O(l))})]-[(2\times \Delta H_f_{(B_5H_9(l))})+(12\times \Delta H_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%285%5Ctimes%20%5CDelta%20H_f_%7B%28B_2O_3%28s%29%29%7D%29%2B%289%5Ctimes%20%5CDelta%20H_f_%7B%28H_2O%28l%29%29%7D%29%5D-%5B%282%5Ctimes%20%5CDelta%20H_f_%7B%28B_5H_9%28l%29%29%7D%29%2B%2812%5Ctimes%20%5CDelta%20H_f_%7B%28O_2%28g%29%29%7D%29%5D)
We are given:

Putting values in above equation, we get:
![\Delta H_{rxn}=[(2\times (-1272))+(9\times (-285.4))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H_{rxn}=-5259kJ](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%282%5Ctimes%20%28-1272%29%29%2B%289%5Ctimes%20%28-285.4%29%29%5D-%5B%282%5Ctimes%20%2873.2%29%29%2B%2812%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H_%7Brxn%7D%3D-5259kJ)
To calculate the amount of heat released for the given amount of
, we use unitary method, we get:
When 2 moles of
reacts, the amount of heat released is 5259 kJ
So, when 0.211 moles of
will react, the amount of heat released will be = 
Hence, the amount of heat released when 0.211 moles of
reacts is 554.8 kJ
Radio waves have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation.
Explanation:
You can test by putting sand in one cup and water in another. Then you put the thermometers in the cups. One you have done that you can use the heat lamp and put both cups under it for the same amount of time. After you do that and recorded your data you are done with the experiment.
Hope this helps :D