Answer: P2O5
Explanation: You divide both subscripts by 2 to get the empirical formula.
The mass percentage of the copper (Cu) in the compound CuSO₄ is 39.81%.
<h3>What is the mass percentage?</h3>
The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.
First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.
Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.
The molecular mass of CuSO₄ = 63.55 + 32.07 + 4(16.0) = 159.62 g.
The mass percentage of the Sulphur = (63.55/159.62) × 100 = 39.81%.
Therefore, the mass percentage of Copper is equal to 39To learn.
Learn more about the mass percentage, visit here:
brainly.com/question/16750428
#SPJ1
Answer:
im pretty sure the answer is b
Answer:
6
Explanation:
The only numbers you count are the ones after the letter H. In this chemical formula there are two H's. If the H didn't have any number after it, it would be 1, but there is a 3 after the first H and a 3 after the other H. Therefore, there is 6 hydrogen atoms.
