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Paha777 [63]
3 years ago
7

Let K and T be the current ages of two siblings Katie and Thomas Katie is currently twice the age of Thomas. In 6 years Katie wi

ll be 4 times Thomas's current age how old are Katie and Thomas
* Write a system of equations to describe the situation
* find the solution to the system and answer the question

Mathematics
1 answer:
Alika [10]3 years ago
7 0

Answer:

Here, K represents the current age of Katie and T represents the current age of Thomas.

(a)

As per the statement:

Katie is currently twice the age of Thomas.

⇒K = 2T                ......[1]

It is also given that in 6 years Katie will be 4 times Thomas's current age.

K+6 = 4T

K+6 = 4T

Subtract 6 from both sides we get;

K = 4T-6                    ......[2]

A system of equations that describe the situation is:

K = 2T

K+6 = 4T

(b)

To find the solution:

equate [1] and [2] we have;

4T-6 = 2T

Subtract 2T from both sides we have;

2T-6 = 0

Add 6 to both sides we get;

2T = 6

Divide both sides by 2 we have;

T = 3 years

Substitute this in equation [1] we get;

K = 2(3) = 6 years.

Therefore, the current age of Katie and Thomas are 6 years and 3 years.




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Cho hàm số y=f(x) có đạo hàm trên R thỏa mãn F'(2x-1)= (x+1)×(x-2)×(x-2)×(x-3). Y= f(x^2+1) đồng biến trên khoảng nào?
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3 years ago
Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,721 was collected on the sale of 1,141 ticket
Alex787 [66]

Step-by-step explanation:

You have two unknowns, two variables, therefore you need to have at least two equations in this word problem in order to find a solution. Let's review the info you are given:

The price of an Adult ticket: $5

The price of a Student ticket: $1

The two variables are: the number of Adult tickets sold (you can use variable "A"), and the number of Student tickets sold (use variable "S").

The other info you are given is the total number of tickets sold: 1,215 tickets. Use this to make your first equation: the number of adult tickets plus the number of student tickets equals 1,215.

You are also told how much money was collected: $2,591. That means, $5 from every Adult ticket and $1 from every student ticket. We don't know how many of each ticket, but we assigned variables A and S to stand in for this unknown info. The money made from all the adult tickets would be the price of the adult ticket times how many adult tickets sold (5 times A), and the money made from all the student tickets would be the price of the student ticket times how many student tickets sold (1 times S). Use this to make your second equation, which says that all the money collected from all the tickets (5 times A in addition to 1 times S) is (=) 2,591.

Now you have two equations, each equation has two variables. To solve, go back to the easiest equation (the first one) and isolate one of the variables. By isolate I mean get it on one side of the equation by itself. Since in this case these variables are being added together, you have to do the opposite of addition, which is of course subtraction. To do this, you will have to subtract the other variable ON BOTH SIDES of the equation. So, say we want to isolate the variable A, we will subtract S from both sides. Well, S minus S is zero, so now A is isolated, meaning the left side of the equation is just A = ...  Now you want to subtract the S on the other side. Remember that whatever you do to one side you must do to the other.

Now that you have your equation re-worked to show A = ..., you need to "plug it into" the second equation. What I mean is, you need to substitute instead of A, put in this equation. Then you will have one equation with one variable which you can solve! Remember the rules of equations, to do work in parenthesis first,  multiply or divide, then add or subtract. You will be able to solve for S.

Once you have found S (the number of student tickets sold), you can easily find A (the number of adult tickets sold) by going back to that first equation and subtracting your value of S from 1215.

HOPE THAT HELP

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