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jasenka [17]
3 years ago
12

Factor the expression x^2-16x+63

Mathematics
1 answer:
Airida [17]3 years ago
7 0
The factors should add to the b value and multiply to the c value.

Final answer: (x-9)(x-7)

Check:
-9*-7=63
-9-7=-16
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A certain type of bird has a probability of 1/12 Harding a bird with white feather. If a bird lays 2 eggs, find the probability
liq [111]
A. \frac{1}{12}*(1-\frac{1}{12})\\\frac{1}{12}*\frac{11}{12}\\\frac{11}{144}

B. \frac{1}{12}*(1-\frac{1}{12})+\frac{1}{12}*\frac{1}{12}\\\frac{1}{12}*\frac{11}{12}+\frac{1}{144}\\\frac{11}{144}+\frac{1}{144}\\\frac{12}{144}\\\frac{1}{12}
6 0
3 years ago
bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye. the table gives the
MAVERICK [17]
Given that Bill is on the school archery team. the target has a center bull's-eye and two rings around the bull's-eye.

Given the table below that gives the probabilities of outcomes.

\begin{tabular}
{|c|c|c|c|c|}
\bold{Outcome}&Bull's-eye&Inner ring&Outer ring&Miss\\
\bold{Probability}&0.036&0.297& 0.423&0.244
\end{tabular}

The probability <span>that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72</span>

Therefore, <span>the probability that Bill will get the next arrow in the inner or outer ring is 0.72</span>
6 0
4 years ago
7(h-4)=2h+17 help plzz
S_A_V [24]
7(h-4) = 2h + 17         distribute to get:
7h - 28 = 2h + 17       subtract 2h from both sides to get:
5h - 28 = 17               add 28 to both sides to get:
5h = 45                      divide 5 from both sides to get:
h = 9
6 0
3 years ago
The state medical school has discovered a new test for tuberculosis. (If the test indicates a person has tuberculosis, the
Inessa [10]

The probability according to the given scenario is:

(a) <em>0.0395</em>

(b) <em>0.95</em>

(c) <em>0.076</em>

The given values are:

  • P(B/A) = 0.79
  • P(A) = 0.05

(a)

The probability that the  b/w has tuberculosis as well as having (+) test will be:

→ P(A \cap B) = P(B/A).P(A)

By substituting the values, we get

→                  = 0.79\times 0.05

→                  = 0.0395

(b)

The probability that a person does not have tuberculosis will be:

→ P(A') = 1-P(A)

→            =1-0.05

→            = 0.95

(c)

The person does not have tuberculosis as well as have a (+) test, the probability will be:

→ P(A' \cap B) = P(A').P(B/A')

→                  = 0.95\times 0.08

→                  = 0.076

Learn more:

brainly.com/question/14816227

8 0
2 years ago
Alex is working to simplify
stich3 [128]

Answer:

is this all?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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