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attashe74 [19]
3 years ago
9

Why are the Oxygens unbalenced?

Chemistry
1 answer:
aalyn [17]3 years ago
7 0

All atoms except oxygen and hydrogen should be balanced first. In acidic conditions, the oxygen atoms should be balanced with water, while hydrogen atoms should be balanced with H+.

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I NEED APPROPRIATE ANSWERS SO IF ANYONE CAN PLEASE ANSWER THESE TWO QUESTIONS I WILL GIVE YOU BRAINIEST. Can someone please help
In-s [12.5K]

Answer:

1. When salt is mixed with water, the salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules

2. Pure sodium explodes on contact with water

Explanation:

5 0
3 years ago
A radioactive element having and atomic number 82 and atomic mass 214 emits a beta particle. The resulting element is:______.
aalyn [17]

Answer:

\frac{214}{83} Bi

Explanation:

In beta emission, a neutron is converted into a proton thereby reducing the neutron:proton (N/P) ratio.

When a beta emission occurs, the mass number remains the same while the nuclear charge increases by one unit. The daughter nucleus is found one place to the right of its parent in the periodic table.

5 0
3 years ago
How do turntables in microwave change how food is heated? Please help me
sdas [7]
It even and equally distributes the heat, therefore giving the food a more thorough cook in the microwave compared to one without a turntable.
8 0
4 years ago
Most galaxies in the universe are irregular-shaped galaxies. True False
klemol [59]
<h2>Hello!</h2>

The answer is: False.

Why?

It's known that most common galaxies are spiral - shaped, but according to some studies, the irregular - shaped galaxies can not be even considered "spiral shaped".

Irregular - shaped are galaxies defined by their lack of structures, and they were formed by an external gravitonal force acting, in fact, it's believed that they were spiral or elliptical galaxies before.

An example of irregular - shaped galaxies is Small Magenallic Cloud.

Have a nice day!

5 0
4 years ago
Read 2 more answers
Copper has a density of 8.96 g/cm3 . if a cylinder of copper weighing 48.85 g is dropped into a graduated cylinder containing 20
Ronch [10]

To solve for the new water level, let us first calculate for the volume of the copper cylinder. The formula we can use is:

V = m / ρ

where V is the volume, m is the mass of the copper and ρ is the density, therefore:

V = 48.85 g / (8.96 g / cm^3)

V = 5.45 cm^3

since cm^3 = mL

V = 5.45 mL

 

The new water level will be the initial volume of the graduated cylinder plus the volume of the copper cylinder, therefore:

new water level = 20 mL + 5.45 mL

new water level = 25.45 mL

5 0
3 years ago
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