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Answer is: Ksp for silver sulfide is 8.00·10⁻⁴⁸.
Reaction
of dissociation: Ag₂S(s) → 2Ag⁺(aq) + S²⁻(aq)<span>.
</span>s(Ag₂S) = s(S²⁻) = 1.26·10⁻¹⁶ M.
s(Ag⁺) = 2s(Ag₂S) = 2.52·10⁻¹⁶ M; equilibrium concentration of silver cations.
Ksp = s(Ag⁺)² · s(S²⁻).
Ksp = (2.52·10⁻¹⁶ M)² · 1.26·10⁻¹⁶ M.
Ksp = 6.35·10⁻³² M² · 1.26·10⁻¹⁶ M.
Ksp = 8.00·10⁻⁴⁸ M³.
Answer:
50.76 mol H2O.
Explanation:
The photosynthesis follows the equation:
6CO2 + 6H2O ---> C6H12O6 + 6O2
This means that 6 mol of H2O are needed to obtain 1 mol of C6H12O6 (see the numbers that precedes every molecule to know how many mols are in game).
So we can say that:
1 mol C6H12O6 --------- 6 mol H2O
8.46 mol C6H12O6 -----x= 8.46 x 6 : 1 = 50.76 mol H20
Answer:
2 atoms of H in the products side
Explanation:
3NO₂ + H₂O → NO + 2HNO₃
In product side: 3 N (1 from NO and 6 from nitric acid), 7 O (6 from nitric acid + 1 from NO), 2 H
In reactant side: 3 N, 7 O (6 from the dioxide + 1 from water) and 2 H
