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Setler [38]
3 years ago
10

Given the line below.

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

y + 1 = \frac{1}{2} (x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - y₁ = m(x - x₁)

where m is the slope and (x₁, y₁ ) a point on the line

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, - 1 ) and (x₂, y₂ ) = (2, 1 )

m = \frac{1-(-1)}{2-(-2)} = \frac{1+1}{2+2} = \frac{2}{4} = \frac{1}{2} and (x₁, y₁ ) = (- 2, - 1 ) , then

y - (- 1) = \frac{1}{2}(x - (- 2) ) , that is

y + 1 = \frac{1}{2} (x + 2)

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MATH QUESTION!! WILL MARK BRAINLIEST!! PAST DUE HELP ASAP!!!
monitta

Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Right Triangles</u>

In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.

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The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.

The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

CM=\frac{1}{2}AB

First, find the coordinates of the midpoint M(xm,ym):

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Thus, the midpoint is M( 1.5 , 2 )

Calculate the distance CM:

CM=\sqrt{(1.5-0)^2+(2-0)^2}

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Now find the distance AB:

AB=\sqrt{(3-0)^2+(4-0)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}

AB=5

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It's proven CM is half of AB

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