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Setler [38]
3 years ago
10

Given the line below.

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

y + 1 = \frac{1}{2} (x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - y₁ = m(x - x₁)

where m is the slope and (x₁, y₁ ) a point on the line

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, - 1 ) and (x₂, y₂ ) = (2, 1 )

m = \frac{1-(-1)}{2-(-2)} = \frac{1+1}{2+2} = \frac{2}{4} = \frac{1}{2} and (x₁, y₁ ) = (- 2, - 1 ) , then

y - (- 1) = \frac{1}{2}(x - (- 2) ) , that is

y + 1 = \frac{1}{2} (x + 2)

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Answer:

11:16

Step-by-step explanation:

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Cancel the 0s then divide by 2.

22/2=11

32/2=16

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Nat2105 [25]

Answer:

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3 years ago
Last night Erin completed 5/6 of the homework assignment. Tom completed 1/3 of the same assignment. How much more of the assignm
Lynna [10]

Answer:

50 more

Step-by-step explanation:

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3 0
3 years ago
Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9
AnnZ [28]

Answer:

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Step-by-step explanation:

We have been given that

f(x)=x^3-27,g(x)=3x-9

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes -  a^3-b^3=(a-b)(a^2+ab+b^2)

f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)

And g(x) can be written as

g(x)=3x-9\\=3(x-3)

Thus, we have

(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}

On cancelling the common factors, we get

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

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