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sveta [45]
3 years ago
5

8*8/4*4+2 Plzzzzzz Helppppppp

Mathematics
2 answers:
m_a_m_a [10]3 years ago
4 0

Answer:

66

Step-by-step explanation:

8*8=64

4*4=16

64/16=4

4*16=64

64+2=66

Pachacha [2.7K]3 years ago
3 0

Answer:

Step-by-step explanation:

32/9

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What is the equation of the quadratic function that has a minimum at (7.-3) and goes through (9.9)?
bixtya [17]

Answer:

X² - 14x + 48= 0

Step-by-step explanation:

To find the quadratic equation well have to look for the root of the equation.

So the roots are at x= 6 and x= 8

The quadratic curve didn't pass the origin .

It intercepted the x axis at 6 and 8 and that's the roots.

So our equation is

(X-6)(x-8)= x²-8x -6x +48

X² - 14x + 48= 0

7 0
3 years ago
grandma jean can make 2 blankets in 3 days if grandma jean needs to make 14 blankets how many days will it take her.
irinina [24]
In order to solve this problem you need to do the following:
3 days = 2 blankets
14/2=7= 7 days
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:)
6 0
3 years ago
A jewelry box has a volume of 14 cubic inches.The area of the base is 8 square inches. what is the height
AlekseyPX
The height of the jewelry box is 1.75. because the equation of a rectangular prism is V=Bh. so we already know the volume and the base so you just divide them and you get your height. 
3 0
3 years ago
Chapter 8: Chapter 8 Test > chapter Test
Vikentia [17]

Answer:

D = sqrt[ (2-4)^2 + (7- (-1))^2] = ~8.2

Step-by-step explanation:

D = sqrt[ (Fx-Gx)^2 + (Fy- Gy)^2]

7 0
3 years ago
Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro
Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9

Then:

P = \frac{40320}{4.43*10^9}*100\%=9.11*10^{-4}\%

5 0
3 years ago
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