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2 years ago

Can you swallow zyn nicotine pouches spit

Chemistry

1 answer:

ryzh [129]2 years ago

5 0

ew, no you can not do that. That is really nasty .

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1.Which of the following compounds give acidic solution with water:

m_a_m_a [10]

Answer:

Explanation:

metallic oxides are basic in nature.

7 0

3 years ago

Read the information about the three atoms given in the table. Which of them are isotopes of each other

lara [203]

I think that the answer could be A. X and Y

5 0

3 years ago

How many molecules of hydrogen gas are produced when 32.4 g of potassium are added to water?

Yuri [45]

Moles of K = 32.4/39 = 0.83 mole. According to stoichiometry, 2 moles of K produces 1mole of H2. Therefore, 0.83 mole of K produces = 0.83/2 = 0.415 moles of H2. Therefore number molecules of H2 = moles of H2 x 6.02 x 10^23 = 2.4983 x 10^23 molecules. Hope this helps!

4 0

2 years ago

What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O

nadya68 [22]

Answer:

$V=43.46mL$

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

$3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O$

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

$n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4$

Then, given the molarity, it is possible to obtain the milliliters as follows:

$V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL$

Best regards!

7 0

2 years ago

Name an acids and a bases

Bumek [7]

Answer:

HCl for acid, NaOH for base.

Explanation:

Acids start with H.

Bases end with OH.

6 0

2 years ago