Answer:
Explanation:
1. Calculate the initial moles of acid and base
2. Calculate the moles remaining after the reaction
OH⁻ + H₃O⁺ ⟶ 2H₂O
I/mol: 0.0053 0.005 00
C/mol: -0.00500 -0.005 00
E/mol: 0.0003 0
We have an excess of 0.0003 mol of base.
3. Calculate the concentration of OH⁻
Total volume = 53 mL + 25.0 mL = 78 mL = 0.078 L
![\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}](https://tex.z-dn.net/?f=%5Ctext%7B%5BOH%7D%5E%7B-%7D%5D%20%3D%20%5Cdfrac%7B%5Ctext%7B0.0003%20mol%7D%7D%7B%5Ctext%7B0.078%20L%7D%7D%20%3D%20%5Ctextbf%7B0.0038%20mol%2FL%7D%5C%5C%5C%5C%5Ctext%7BThe%20final%20concentration%20of%20OH%24%5E%7B-%7D%24%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B0.0038%20mol%2FL%7D%7D%24%7D)
The hydrogen bonding tendency of water causes it to be 'sticky,' in that water molecules tend to stick together (as in a puddle). This is known ascohesion. Because of this property, water has a high surface tension. This means that it takes a little extra force to break the surface of the water puddle.Mar 13, 2018
The mass of GeCl4 that would be formed will be 1.51 g
<h3>Stoichiometric calculations</h3>
From the balanced equation of the reaction:
Ge (s) + 2Cl2 (g) →GeCl4
The mole ratio of Ge and Cl2 is 1:2.
Mole of 1.0 g Ge: 1/72.64
= 0.01377 mole
Mole of 1.0 g Cl2 = 1/71
= 0.01408 mole
Thus, Cl2 is limiting.
Mole ratio of Cl2 and GeCl4 = 2:1
Equivalent mole of GeCl4 = 0.01408/2
= 0.0070 mole
Mass of 0.0070 mole GeCl4 = 0.0070 x 214.4
= 1.51 g
More on stoichiometric calculations can be found here: brainly.com/question/8062886
They all have something to do with heat
