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3 years ago

5

Which of the following is the best example of an open system? (2 points)

2 answers:

Vsevolod [243]3 years ago

6 0

An open system is a system in which both heat and mass are escaping/coming in. (Think of a glass of water; water is evaporating and heat is melting the ice). A closed system is when only heat is escaping/coming in (A bottle of water where water vapor can't escape, but it can still be warmed) An isolated system occurs when neither heat nor mass can escape/come in (Think of a thermos; neither heat nor vapor can escape). Hope this helps!

Dmitriy789 [7]3 years ago

5 0

1) A Car engine.............. Hope it helps, Have a nice day :)

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A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base

yawa3891 [41]

Answer:

11.39

Explanation:

Given that:

$pK_{b}=4.82$

$K_{b}=10^{-4.82}=1.5136\times 10^{-5}$

Given that:

Mass = 1.805 g

Molar mass = 82.0343 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{1.805\ g}{82.0343\ g/mol}$

$Moles= 0.022\ moles$

Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.022}{0.055}$

Concentration = 0.4 M

Consider the ICE take for the dissociation of the base as:

B + H₂O ⇄ BH⁺ + OH⁻

At t=0 0.4 - -

At t =equilibrium (0.4-x) x x

The expression for dissociation constant is:

$K_{b}=\frac {\left [ BH^{+} \right ]\left [ {OH}^- \right ]}{[B]}$

$1.5136\times 10^{-5}=\frac {x^2}{0.4-x}$

x is very small, so (0.4 - x) ≅ 0.4

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x = 2.4606×10⁻³ M

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Q #13 How many moles of MgCl2 are there in 350. g of compound?

Vaselesa [24]

<u>Answer:</u>

3.67 moles

<u>Step-by-step explanation:</u>

We need to find out the number of $MgCl_2$ moles present in 350 grams of a compound.

Molar mass of $Mg$ = 24.305

Molar mass of $Cl_2$ = 35.453

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1 Mole in 1 molecule of $MgCl_2$ = $\frac{1}{95.211} = 0.0105$

Therefore, number of moles in 350 grams of compound = 0.0105 * 350

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