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Dmitriy789 [7]
4 years ago
5

Which property provides the best evidence that the unknown substance is a solid

Chemistry
1 answer:
agasfer [191]4 years ago
7 0
The shape would be the answer if it is taking up space it's a liquid if if it stays in the area of space it's a solid
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Lera25 [3.4K]
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3 years ago
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What is the significance of the Schrödinger wave equation to the quantum mechanical model of
pentagon [3]

Answer:

Quantum Mechanical Model of Atom

The solution of the wave equation brings the idea of shells, sub-shells and orbitals. The probability of finding an electron at a point within an atom is proportional to the |ψ|2 at that point, where ψ represents the wave-function of that electron.

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4 0
3 years ago
Burning magnesium gives us magnesium oxide. This is an example of a reaction.
frez [133]

Answer: -

Oxidation, Oxygen

Explanation: -

Burning of magnesium gives us magnesium oxide.

The chemical symbol of magnesium is Mg.

The chemical symbol of magnesium oxide is MgO.

So, the balanced chemical equation is

2Mg + O2 – 2 MgO.

We see that the element added is O Oxygen. So, the reaction is oxidation.

In oxidation always, oxygen is the common element involved in all chemical reactions of this kind.

5 0
4 years ago
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Which of the following describes a circular current in a fluid that
Vanyuwa [196]

Answer:

C- convection (convectional current)

Explanation:

Convection occurs in fluids e.g gases and liquids. It is the prices by which heat energy is transferred in a fluid by the actually movement of the heated fluid.

It is also called convectional current when the term current is used in the question.

8 0
3 years ago
A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature o
Zielflug [23.3K]

Answer:

Cv_{calorimeter}=18.4kcal/K

Explanation:

Hello!

In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

Q_{hamburguer}=-Q_{calorimeter}

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

Q_{hamburguer}=-Cv_{calorimeter}\Delta T

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K

Best regards!

4 0
3 years ago
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