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4 years ago

Which property provides the best evidence that the unknown substance is a solid

Chemistry

1 answer:

agasfer [191]4 years ago

7 0

The shape would be the answer if it is taking up space it's a liquid if if it stays in the area of space it's a solid

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Can some one help I'm lost iam being timed:( Show using two conversion factors how you would convert from 0.020 kg into mg

dezoksy [38]

Answer:

20000 Mg

Explanation:

5 0

3 years ago

Consider the reaction 2 CO + O2 → 2 CO2 .What is the percent yield of carbon dioxide

Wewaii [24]

Answer:

$Y=50.9\%$

Explanation:

Hello,

In this case, given the reaction, we can directly compute the theoretically yielded grams of carbon dioxide, considering the 2:2 molar ratio between carbon monoxide (molar mass = 28 g/mol) and carbon dioxide (molar mass = 44 g/mol) and the initial reacting grams of carbon monoxide in excess oxygen:

$m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}*\frac{44gCO_2}{1molCO_2} =15.7gCO_2$

Thus, as only 8 g were actually yielded, we compute the percent yield:

$Y=\frac{8g}{15.7g}*100\% \\\\Y=50.9\%$

Best regards.

7 0

3 years ago

classify the materials based on their composition rock, clear liquids, peppercoms, concrete, salt, oxygen, birdseed, plant

USPshnik [31]

Answer:

1. rocks are composed of grains of minerals which are formed by the longest natural chemical reaction

2. clear liquids are mainly sugar and water . they are transparent food and mainly are beverages , ice , grains etc stuff

3. concrete is made up of basically three components . water , aggregate ( rock , sand and gravel ) and portland cement .

4. salt consist of NaCl it is made up of sodium and chloride it is also called rock or halite salt

Explanation:

6 0

3 years ago

The balanced equation for the combustion of Hexane,C6H14 , is

shusha [124]

Answer:

$2C _{6}H _{14} + 19O _{2}→12CO _{2} +14H _{2} O$

3 0

3 years ago

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0

3 years ago