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Archy [21]
3 years ago
6

What is the speed of each vehicle? (Remember S=d/t)

Chemistry
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

A: 20 km/h, B: 10 km/h

Explanation:

Speed of Vehicle A = 40-20/ 2-1

=20 km/h

If A is 20km/h, B is 10km/h as given in option

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The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If the
aleksley [76]

Answer:

It will require<u> second round</u> of the cycle to release 14C0_2

Explanation:

<u>Reason behind the requirement of second round of the cycle to release </u>CO_2 -:

The C4 carbon of succinyl CoA is acetyl from acetyl CoA. Succinyl CoA is converted to succinate, which is then converted to fumarate, fumarate, malate, and eventually oxaloacetate. 14C will be found in oxaloacetate at either C1 or C4. During the second round of the loop, each of these carbons will be converted to carbon dioxide.

7 0
2 years ago
Calculate the atomic mass of oxygen if the three common isotopes of oxygen have masses of 15.995 amu (99.759% abundance), 16.995
Valentin [98]

Answer:

16 amu

Explanation:

6 0
3 years ago
ΚΕ:<br> m.22<br> 2<br> What is the kinetic energy of 10kg dog running with a velocity of 12m/s?
BigorU [14]

Answer:

The answer is

<h2>720 Joules</h2>

Explanation:

The kinetic energy of a body can be found by using the formula

<h3>K.E =  \frac{1}{2}  {mv}^{2}</h3>

where

m is the mass

v is the velocity / speed

From the question

mass = 10 kg

velocity = 12 m/s

Substitute the values into the above formula and solve

That's

<h3>KE =  \frac{1}{2}  \times 10 \times  {12}^{2}  \\   = 5 \times 144  \:  \:</h3>

We have the final answer as

<h3>720 Joules</h3>

Hope this helps you

3 0
3 years ago
The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br_2(g

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}

Given: -\frac{d[HBr]}{dt}]=0.301

Putting in the values we get:

\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}

+\frac{1d[Br_2]}{dt}=0.151

Thus the rate of appearance of Br_2 is 0.151

8 0
3 years ago
Why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions
Alika [10]
<span>Scientists ignore the forces of attraction between particles in a gas under ordinary conditions</span><span> because the particles in a gas are apart and moving fast, rather than clustered and moving slow, therefore the forces of attraction are too weak to have a visible effect.</span>
3 0
3 years ago
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