Answer: P2O5
Explanation: You divide both subscripts by 2 to get the empirical formula.
Answer:
the change in energy of the gas mixture during the reaction is 227Kj
Explanation:
THIS IS THE COMPLETE QUESTION BELOW
Measurements show that the enthalpy of a mixture of gaseous reactants increases by 319kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -92kJ of work is done on the mixture during the reaction. Calculate the change of energy of the gas mixture during the reaction in kJ.
From thermodynamics
ΔE= q + w
Where w= workdone on the system or by the system
q= heat added or remove
ΔE= change in the internal energy
q=+ 319kJ ( absorbed heat is + ve
w= -92kJ
If we substitute the given values,
ΔE= 319 + (-92)= 227 Kj
With the increase in enthalpy and there is absorbed heat, hence the reaction is an endothermic reaction.
Evaporation and transpiration
Answer:
6amu
Explanation:
mass=proton+neutron
mass of cl2=2(16+16)=64amu
Answer:
Separation technique used to separate mud and water without heating:
<u>Sedimentation-Decantation</u>
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Explanation:
<em>1.The settling of the heavier particle at the bottom when the container is left undisturbed is called </em><u><em>sedimentation.</em></u>
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<u><em>In a mixture of Mud and water :</em></u>
In this process the heavy mud particles settle at the bottom due to their high density .
2. Decantation : It is the process of pouring out the upper clear layer of the light particles.
<u><em>In a mixture of Mud and water :</em></u>
The water is lighter and form a clear layer over the settled mud particles. Hence by decantation the clear water is poured into a clean separate container
Thus mud remain in the bottom and the mixture is separated
