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GREYUIT [131]
3 years ago
7

The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58

cal of heat.
Chemistry
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

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yarga [219]

Answer:

E) are electrically attracted to each other

Explanation:

Water molecule is polar because there is a difference in electronegativity values between hydrogen and oxygen. The hydrogen side of the molecule has a slight positive charge and the oxygen side is slightly negatively.  

Positively and negatively charged ends cause water molecules to attract one another and for this reason water shows the properties mentioned in the question: cohesion, high specific heat, and high heat of vaporization.

3 0
3 years ago
Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
Sodium react gently with water ture or false<br>​
Maksim231197 [3]

false,

sodium has a vigorous reaction with water.

This can be observed by putting a piece of sodium in water,

it moves swiftly across the surface of water and reacts violently.

5 0
3 years ago
Of the following, ________ should have the highest critical temperature. Of the following, ________ should have the highest crit
3241004551 [841]

Answer:

H2

Explanation:

Critical temperature is the temperature above which gas cannot be liquefied, regardless of the pressure applied.

Critical temperature directly depends on the force of attraction between atoms, it means stronger the force of higher will be the critical temperature. So, from the given options H2 should have the highest critical temperature because of high attractive forces due to H bonding.

Hence, the correct option is H2.

5 0
3 years ago
At ground level, how are rain and hail similar?
Varvara68 [4.7K]

Answer:

rain is water in molten state

hails are water in solid form.

hope it helps

Plz mark me as brainleist if helps

Have a great day ahead

3 0
2 years ago
Read 2 more answers
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