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GREYUIT [131]
4 years ago
7

The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58

cal of heat.
Chemistry
1 answer:
Umnica [9.8K]4 years ago
5 0

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

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Two waves were analyzed with some high-tech instrumentation. The first wave was found to have a wavelength of 3 x 10 m and the s
a_sh-v [17]

Explanation:

The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m

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The relation between frequency and wavelength is given by :

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f_1=\dfrac{c}{\lambda_1}\\\\f_1=\dfrac{3\times 10^8}{3\times 10^5}\\\\=1000\ Hz

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3 years ago
PLEASE HELP! How does one determine how much of a molecule is produced in a reaction?
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3 years ago
A gold nugget has a density of 38.6g/cm3 and a mass of 270.2. what is its volume?​
aivan3 [116]

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5 0
3 years ago
Read 2 more answers
HELPPPPPPPPPPPP
erica [24]

Answer:

Pressure inside soda can = 5.56 atm

Explanation:

Given data:

Initial volume = 1250 mL

Initial pressure = 1.00 atm

Final volume = 225  mL

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.00 atm × 1250m L =  P₂ × 225 mL

P₂ =  1250 atm. mL/ 225 mL

P₂ = 5.56 atm

8 0
3 years ago
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