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3 years ago

How do you solve 821*54 using an area model

Mathematics

1 answer:

SpyIntel [72]3 years ago

8 0

Answer:

800 20 1

50| | | |

4 | | | |

pretty much a rectangle with 800 20 1 at the top

50 4 on the side

and split the numbers in the box - i tried to recreate it as much as possible

oh then in each little box you have to multiply the numbers so

50 x 800 = 40,000 in the box

50 x 20 = 1,000 in the next box

50 x 1 = 50 in the next box

4 x 800 = 3,200

4 x 20 = 80

4 x 1 = 4

then you add all of them which would be 44,334

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1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Read more about proportions at:

brainly.com/question/21126582

8 0

2 years ago

Which of the following would best represent a cosine function with an amplitude of 2, a period of pi over 3, and a midline at y

OleMash [197]

C. f(x) = – 2 cos 6x + 1

Start by determining the amplitude. Since we've deduced the amplitude is 2, the equation can include either a positive or negative 2 (since amplitude measures absolute value).

Next is the period. The equation for period P is P = (2pi)/b. If P is pi/3, then
pi/3 = (2pi)/b. Thus your b value should be 6.

Finally, the midline would be given by + 1 since adding a unit shifts the function upwards. This means that instead of the highest y value being 2 and the lowest -2, instead you'd have values of 3 and -1.
(3 – 1)/2 = 1 (midpoint theory).

3 0

3 years ago

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Use the Pythagorean Theorem to find the m 14.1 X X= 14.7

KATRIN_1 [288]

Answer:

x = 4.2

Step-by-step explanation:

14.1² + x² = 14.7²

198.81 + x² = 216.09

216.09 - 198.81 = 17.28

√17.28 = 4.15

x = 4.15

Round to nearest tenth

x = 4.2

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2 years ago

Evaluate 8y-10 for y=3

garri49 [273]

8 (3)-10
24-10=14
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3 years ago

2 box plots. The number line goes from 60 to 79. For the swim team, the whiskers range from 64 to 74, and the box ranges from 71

mestny [16]

Answer:

2 and 5

Step-by-step explanation:

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3 years ago

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