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garik1379 [7]
2 years ago
11

Help please i need help on this question

Mathematics
1 answer:
cupoosta [38]2 years ago
4 0

9514 1404 393

Answer:

  A: range

  B: 0 ≤ f(x) ≤ 6

Step-by-step explanation:

<h3>Part A</h3>

As is often the case in multiple-part multiple-choice questions, the answer to the first part is found in the second part. The "<em>range</em>" is the set of all possible output values.

__

<h3>Part B</h3>

The range is the vertical extent of the graph. This graph goes from a minimum of 0 to a maximum of 6 and includes every value in between. The range is ...

  0 ≤ f(x) ≤ 6

_____

<em>Additional comment</em>

You should discuss this question with your teacher. The left inequality symbol on the bottom line is pointed the wrong way.

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Find the average value of the function f(t)=(t-2)^2 on [0,6]
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Answer:

2

Step-by-step explanation:

The "average value of function f(x) on interval [a, b] is given by:

                      f(b) - f(a)

ave. value = ---------------

                         b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2.  For b = 6, we get:

          f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16

For a = 0, we get:

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Plugging these results into the ave. value function shown above, we get:

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                         6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.


4 0
3 years ago
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3 years ago
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