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Yuki888 [10]
3 years ago
7

Explain a trend or pattern you observe in the graph?

Biology
1 answer:
frutty [35]3 years ago
3 0

Answer:

<u>The heavier the hummingbird, the fewer times its wing will beat per second. </u>

Explanation:

There is a negative slope in a graph respective to the components of the x and y axis. Therefore, heavier the hummingbird -> less beats per second.

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Look at the ocean system below.
shepuryov [24]

Answer:

All the other animals that depend on it will go down

Explanation:

Then all the animals will be fighting over food and then it will become survival of the fittest

4 0
3 years ago
Olivia says global warming can't be real because a blizzard in her town last winter lasted four days. How would you explain to O
BartSMP [9]

Answer:B.) Global warming causes air to be moister, resulting in more frequent blizzards.

Explanation:

3 0
3 years ago
The arm or forelimb of humans, horses, goats, and mice all exhibit the same three bone structures: humerus, ulna, and radius. Wh
evablogger [386]

Answer:

A)The limb bones are similar across these species because they share a common ancestor.

Explanation:

The forelimb of humans, horses, goats, and mice are homologous organs. Homologous organs are those which are similar in origin but dissimilar in function. These organs are made of the same bones humerus, ulna, and radius. The above for limb in the given animals perform different functions as they live in different habitats. The homologous structures indicates divergent evolution.

8 0
3 years ago
Read 2 more answers
In shorthom cattle, hair color is governed by co-dominant alleles Red alleles are co-dominant with
Lemur [1.5K]

2. In crossing a homozygous recessive with a heterozygote, what is the chance of ... In cattle, roan color (mixed red and white hairs) occurs in the heterozygous (Rr) ... with another roan (Rr x Rr), will result in 1:2:1 genotypic and phenotypic ratio. ... In humans, the allele for short fingers is dominant over that for long fingers.Answer:

Explanation:

6 0
3 years ago
Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the
erastova [34]

Complete question:

Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.

A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.

Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).

Answer:

The probability that the second child will also have the disease is 1/16.

Explanation:

<u>Available data:</u>

  • Two genes independently inherited: one for blood type, the other for disease
  • Man with type A blood  x  Woman with type B blood
  • Both parents are heterozygous for the gene that causes the disease; Dd

If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.

Cross:  

Parentals)           AiDd         x      BiDd

Gametes)  AD  Ad  iD  id       BD  Bd  iD  id

Punnett square)      AD       Ad       iD       id

                     BD   ABDD  ABDd  BiDD BiDd

                     Bd   ABDd   ABdd   BiDd Bidd

                     iD    AiDD    AiDd    iiDD   iiDd

                     id    AiDd     Aidd     iiDd    iidd

F1) <u>Genotype</u>:

1/16 ABDD

2/16 ABDd

1/16 ABdd

1/16 AiDD

1/16 BiDD

2/16 AiDd

2/16 BiDd

1/16 Aidd

1/16 Bidd

1/16 iiDD

2/16 iiDd

1/16 iidd

<u>Phenotype:</u>

3/16 A/B normal

4/16 A normal

4/16 B normal

3/16 0 normal

1/16 0 affected by the disease.

3 0
3 years ago
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