Circumference + perimeter =38
x = circumference of circle
find r in terms of x
2
r=x
r=
Area=
r^2
so..
A=
(
)^2
=
(
)
=
(38-x) is perimeter
then
(
)^2
+ (
)^2
then you graph it and it equals
16.716 cm the circumference of the circle
BE is parallel to CD, therefore, m∠BEC=m∠ECD, therefore mBC=mDE
BE is the diameter, so Arc BE is 180 degree
mBC+mCD+mDE=180
replace mCD with 3mBC, and replace mDE with mBC: mBC+3mBC+mBC=180
5mBC=180
mBC=180/5=36
mCD=3mBC=3*36=108
the inscirbed angle m∠ECD= the measure of arc DE=36
The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
Answer:
(3,2)
Step-by-step explanation:
Here's your given:
y = 4x - 10
y = 2
Because they both equal y, that means they equal each other:
2 = 4x - 10
Add 10 on both sides:
12 = 4x
Then, divide 4 on both sides:
3 = x
This represents the x coordinate.
Normally you would put this value into one of the equations to figure out y, but they already gave us that in the beginning:
y = 2
This represents the y coordinate.
Put the two values together to get: (3,2)
<h2>im pretty sure it is... 56,280?</h2>
